Makefile 中的递归...还有其他解决方案吗？

发布于 2024-12-08 04:18:44 字数 473 浏览 0 评论 0原文

我想要做的是压缩某个文件夹下所有子文件夹中的所有css。

例如，我有

/resources/css/
/resources/css/parent.css
/resources/css/child.css
/resources/css/import/import.css

这样的东西......（上面只是一个例子，文件名在现实世界中没有使用）。

因此，我尝试在 Makefile 中搜索递归。但似乎这不是推荐的方法，但后来被告知使用“include”并在每个子文件夹下都有 Makefile，并且最父级的 Makefile 应该调用子文件夹的 Makefile。

但！我不喜欢这种做法。我不想为每个子文件夹创建 Makefile。

还有其他方法可以处理这种情况吗？任何其他工具建议，我愿意学习和尝试。

我只想执行一个简单的命令来压缩我的文件夹下的所有 css。（甚至是js）。谢谢！

原文

What I want to do is to compress all css in all subfolders under a certain folder.

for example, I have

/resources/css/
/resources/css/parent.css
/resources/css/child.css
/resources/css/import/import.css

something like this... (above is just an example, file names are not being used in real-world).

So, I tried searching for doing recursion in Makefile. But seems like it's not a recommended way, but then was told to use "include" and have Makefile under each sub-folders and the most parent Makefile should call sub-folder's Makefile.

But! I don't like this way of doing. I don't want to create Makefile for every sub-folder.

Is there a other way to handle this case? Any other tool suggestions, I'm willing to learn and try out.

I just want to do simple one command to compress all the css under my folder. (even js).
Thanks!

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于我来说 2024-12-15 04:18:44

在你的 Makefile 中，

# Define a variable that encompasses all of the CSS files:
CSSFILES := $(shell find . -name '*.css')

# Target compressed versions of each
default: $(CSSFILES:%.css=%.compressed.css)

# Tell Make how to compress (tab leading command line)
%.compressed.css: %.css
        compresscommand --input lt; --output $@

In your Makefile,

# Define a variable that encompasses all of the CSS files:
CSSFILES := $(shell find . -name '*.css')

# Target compressed versions of each
default: $(CSSFILES:%.css=%.compressed.css)

# Tell Make how to compress (tab leading command line)
%.compressed.css: %.css
        compresscommand --input lt; --output $@

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