配置“深度”与 Unity IoC 的依赖关系

Question

假设我的 MVC 2 项目中有以下类和接口：

存储库：

IRepository1、IRepository2、IRepository3

public class ConcreteRepository1 : IRepository1
{
     public ConcreteRepository1()
     {
         ...
     }
     ...
}

public class ConcreteRepository2 : IRepository2
{
     public ConcreteRepository2()
     {
         ...
     }
     ...
}

public class ConcreteRepository3 : IRepository3
{
     public ConcreteRepository3()
     {
         ...
     }
     ...
}

服务类：

public class Service1
{
    private IRepository1 repo1;
    private IRepository2 repo2;

    public Service1(IRepository1 repo1, IRepository2 repo2)
    {
        this.repo1 = repo1;
        this.repo2 = repo2;
    }
    ...
}

控制器：

public class Controller1 : Controller
{
    private Service1 srv1;
    private Service2 srv2;

    public Controller1(Service1 srv1, Service2 srv2)
    {
        this.srv1 = srv1;
        this.srv2 = srv2;
    }
    ...
}

我有自定义的 ControllerFactory，并且我知道如何将具体存储库与接口联系起来：

IUnityContainer container = new UnityContainer();
container.RegisterType<IRepository1, ConcreteRepository1>(new TransientLifetimeManager(), new InjectionConstructor());
container.RegisterType<IRepository2, ConcreteRepository2>(new TransientLifetimeManager(), new InjectionConstructor());
container.RegisterType<IRepository3, ConcreteRepository3>(new TransientLifetimeManager(), new InjectionConstructor());

问题是我应该如何注册服务我的自定义 ControllerFactory 中的“实例和控制器”类型，使统一容器解析整个层次结构 Controller->Service->Repository 并避免在内部调用 Resolve控制器或服务？

谢谢。

Answer 1

如果你已经注册了IRepository1-3，那么你可以获取Service1实例，只需调用

container.Resolve<Service1>()

container.Resolve()就会自动解析依赖项并将创建 Controller1 类型的实例。

示例：

public interface IRepository1 { }
public interface IRepository2 { }
public interface IRepository3 { }

public class ConcreteRepository1 : IRepository1 { }
public class ConcreteRepository2 : IRepository2 { }
public class ConcreteRepository3 : IRepository3 { }

public class Service1
{
    private IRepository1 repo1;
    private IRepository2 repo2;

    public Service1(IRepository1 repo1, IRepository2 repo2)
    {
        this.repo1 = repo1;
        this.repo2 = repo2;
    }
}

public class Service2
{
    private IRepository1 repo1;
    private IRepository2 repo2;

    public Service2(IRepository1 repo1, IRepository3 repo3)
    {
        this.repo1 = repo1;
        this.repo2 = repo2;
    }
}

public class Controller1
{
    private Service1 srv1;
    private Service2 srv2;

    public Controller1(Service1 srv1, Service2 srv2)
    {
        this.srv1 = srv1;
        this.srv2 = srv2;
    }
}

解析：

var container = new UnityContainer();
container.RegisterType<IRepository1, ConcreteRepository1>();
container.RegisterType<IRepository2, ConcreteRepository2>();
container.RegisterType<IRepository3, ConcreteRepository3>();

var controller = container.Resolve<Controller1>();

编辑：

public interface IRepository { }
public class Repository : IRepository { }

public class Service
{
    //[InjectionConstructor]
    public Service()
    {
        Console.WriteLine("Parameterless constructor called");
    }

    public Service(IRepository repository)
    {
        Console.WriteLine("Contructor with IRepository called");
    }
}

private static void Main()
{
    var container = new UnityContainer();
    container.RegisterType<IRepository, Repository>();
    var service = container.Resolve<Service>();
    container.RegisterType<Service>(new InjectionConstructor());
    var service2 = container.Resolve<Service>();
}

输出：

Contructor with IRepository called
Parameterless constructor called

因此，当我们没有注册 Service 时（换句话说，它具有默认解析行为），Unity 会构造 Service< /code> 默认使用最贪婪的构造函数。当您指定 new InjectionConstructor() 时，这会告诉 Unity 使用无参数构造函数。如果您使用 InjectionConstructorAttribute 标记构造函数（在本例中为 public Service()），也会收到相同的行为。

Answer 2

当然只是以下内容 -

container.RegisterType<Service1>(new TransientLifetimeManager(), new InjectionConstructor());

对于 Service2 也是如此。 IoC容器将为你构造对象