Popen 与 PIPE 通信无法捕获进程的所有输出

发布于 2024-12-07 23:52:21 字数 702 浏览 0 评论 0原文

我正在尝试运行 python 脚本并捕获它的输出。似乎在第一个输出行之后，它重定向到控制台而不是我的字符串。 Manage.py 是一个用于管理 Django 项目的命令行实用程序，例如启动生产服务器或运行单元测试。

这是我的代码：

import os, string, datetime
from subprocess import Popen, PIPE

def runProcess(command, parameters):
    process =  Popen([command]+parameters, stdout=PIPE)
    output=process.communicate()[0]
    return output

testStatus=runProcess('python',['manage.py','test','coffeebean'])

print ("*****Own output*****")
print(testStatus)

这是输出：

Ran 1 test in 0.000s

OK
*****Own output*****
Creating test database for alias 'default'...
Destroying test database for alias 'default'...

为什么第一行没有被捕获？

此致，丹尼尔

原文

I'm trying to run a python script and capture the output of it. It seems like after the first output line it redirects to the console instead of to my string. Manage.py is a command-line utility for managing Django projects, like starting the production server or running unit tests.

This is my code:

import os, string, datetime
from subprocess import Popen, PIPE

def runProcess(command, parameters):
    process =  Popen([command]+parameters, stdout=PIPE)
    output=process.communicate()[0]
    return output

testStatus=runProcess('python',['manage.py','test','coffeebean'])

print ("*****Own output*****")
print(testStatus)

This is the output:

Ran 1 test in 0.000s

OK
*****Own output*****
Creating test database for alias 'default'...
Destroying test database for alias 'default'...

Why are the first lines not catched?

Best regards,
Daniel

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夜光 2024-12-14 23:52:21

因为它们被写入 stderr，而不是 stdout。尝试

def runProcess(command, parameters):
    process = Popen([command]+parameters, stdout=PIPE,stderr=PIPE)
    return process.communicate()

out,err =runProcess('python',['manage.py','test','coffeebean'])

print ("*****Own output*****")
print(out)
print ("*****Own error output*****")
print(err)

Because they're written to stderr, not stdout. Try

def runProcess(command, parameters):
    process = Popen([command]+parameters, stdout=PIPE,stderr=PIPE)
    return process.communicate()

out,err =runProcess('python',['manage.py','test','coffeebean'])

print ("*****Own output*****")
print(out)
print ("*****Own error output*****")
print(err)

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