tsql 不同计数子查询
我正在使用 SSMS 2008,我需要使用子查询来返回唯一记录/客户端的计数。我该怎么做?目前,我正在返回整个数据集的所有唯一记录,而不是每个客户端。这是我目前的伪代码:
SELECT A.Program, A.PEOPLE_ID, K.EVENT_NAME, A.Program2, A.Program3
(SELECT COUNT(DISTINCT K.EVENT_NAME)
FROM #TEMP1 A, evolv_cs.dbo.facility_view F, evolv_cs.dbo.people_x N, event_view K WITH (NOLOCK)
WHERE F.group_profile_id = A.group_profile_id AND
K.event_definition_id = a.event_definition_id AND
A.people_id = N.people_id
GROUP BY K.EVENT_NAME) as DistinctEvent
FROM #TEMP1 A
JOIN event_view K WITH (NOLOCK) on K.event_definition_id = A.event_definition_id
WHERE @START_DATE BETWEEN A.Enrolled_Date AND DATEADD(D, 14, A.Enrolled_Date)
AND (@SERVICE IS NULL OR @SERVICE = K.event_name)
GROUP BY
A.Program, A.PEOPLE_ID, K.EVENT_NAME, A.Program2, A.Program3
好的,我现在编辑了上面的查询。我仍然想要每个客户端的 event_name 。
I am using SSMS 2008 and I need to use a subquery to return the count of unique records / client. How do I do this? Currently I am returning all unique records over the whole dataset and not per client. Here is my pseudocode currently:
SELECT A.Program, A.PEOPLE_ID, K.EVENT_NAME, A.Program2, A.Program3
(SELECT COUNT(DISTINCT K.EVENT_NAME)
FROM #TEMP1 A, evolv_cs.dbo.facility_view F, evolv_cs.dbo.people_x N, event_view K WITH (NOLOCK)
WHERE F.group_profile_id = A.group_profile_id AND
K.event_definition_id = a.event_definition_id AND
A.people_id = N.people_id
GROUP BY K.EVENT_NAME) as DistinctEvent
FROM #TEMP1 A
JOIN event_view K WITH (NOLOCK) on K.event_definition_id = A.event_definition_id
WHERE @START_DATE BETWEEN A.Enrolled_Date AND DATEADD(D, 14, A.Enrolled_Date)
AND (@SERVICE IS NULL OR @SERVICE = K.event_name)
GROUP BY
A.Program, A.PEOPLE_ID, K.EVENT_NAME, A.Program2, A.Program3
OK, I edited the above query now. I still want event_name per client.
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您要在此处使用的是用于不同计数的 GROUP BY 子句,而不是连接的子查询。以下两个查询应该可以满足您的需求。
如果您需要将查询结果合并到一个结果集中,您应该可以使用 UNION 来实现。
What you want to use here is the GROUP BY clause for your distinct counts, instead of the joined subqueries. The following two queries should give you what you want.
If you need to combine the results of the queries into a single result set, you should be able to do so with a UNION.