Ruby 搜索多维数组

发布于 2024-12-07 17:35:11 字数 410 浏览 0 评论 0原文

学习 Ruby 代码的美妙之处，我想知道是否有一种简单/直接的方法可以在多维数组中进行搜索。我有一个包含 4 个索引的多数组，其中包含各种数字。我想搜索与另一个数组匹配的内容的每个索引...seudo codez

multi_array = [ [1,3,7], [3,1,4], [1,3,4], [0,9,2]]
numbers_looking_to_match = [1,5,9]
multi_array.each do | elmt |
  elmt.each_with_index do |elmt, idx|
    if elmt == numbers_looking_to_match.each { |e| puts "match" }
  end 
end

我希望它返回一个新的多数组，并删除原始多数组的所有不匹配字符。

原文

Learning the beauty of Ruby code and I was wondering if there is a simple/straightforward to search within a multidimensional array. I have an multi array with 4 indices that contain assorted number. I want to search though each index matching the contents agains another array...seudo codez

multi_array = [ [1,3,7], [3,1,4], [1,3,4], [0,9,2]]
numbers_looking_to_match = [1,5,9]
multi_array.each do | elmt |
  elmt.each_with_index do |elmt, idx|
    if elmt == numbers_looking_to_match.each { |e| puts "match" }
  end 
end

I want this to return a new multi array with all non matching characters removed for original multi array.

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烟酒忠诚 2024-12-14 17:35:11

使用 Array#& 对于交叉点，

multi_array.map {|a| a & numbers_looking_to_match }

Using Array#& for intersection,

multi_array.map {|a| a & numbers_looking_to_match }

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习惯成性 2024-12-14 17:35:11

multi_array.each { |elem| number_looking_to_match.each { |x| elem.delete(x) if elem.include?(x)} }

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她说她爱他 2024-12-14 17:35:11

要擦除不需要的字符的每个元素：

require 'set'
multi_array=[ [1,3,7], [3,1,4], [1,3,4], [0,9,2]]
numbers_looking_to_match=Set.new([1,5,9])

scrubbed=multi_array.collect{ |el|
  numbers_looking_to_match.intersection(el).to_a
}

puts scrubbed.inspect
# prints [[1], [1], [1], [9]]

To scrub each element of unwanted characters:

require 'set'
multi_array=[ [1,3,7], [3,1,4], [1,3,4], [0,9,2]]
numbers_looking_to_match=Set.new([1,5,9])

scrubbed=multi_array.collect{ |el|
  numbers_looking_to_match.intersection(el).to_a
}

puts scrubbed.inspect
# prints [[1], [1], [1], [9]]

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