“Min xfer”是什么意思？和“吞吐量”在 IOzone 的输出中
我是 IOzone 的新用户，当我使用以下命令运行 IOzone 时：./iozone -i 0 -i 1 -t 2 -T，它会生成以下结果（部分）：
使用的命令行：./iozone -i 0 -i 1 -t 2 -T 输出以千字节/秒为单位 时间分辨率 = 0.000001 秒。 处理器缓存大小设置为 1024 KB。 处理器高速缓存行大小设置为 32 字节。 文件步长设置为 17 * 记录大小。 2个线程的吞吐量测试 每个线程将 512 KB 文件写入 4 KB 记录
Children see throughput for 2 initial writers = 650943.69 KB/sec
Parent sees throughput for 2 initial writers = 13090.24 KB/sec
Min throughput per thread = 275299.72 KB/sec
Max throughput per thread = 375643.97 KB/sec
Avg throughput per thread = 325471.84 KB/sec
Min xfer = 356.00 KB
Children see throughput for 2 rewriters = 1375881.50 KB/sec
Parent sees throughput for 2 rewriters = 10523.74 KB/sec
Min throughput per thread = 1375881.50 KB/sec
Max throughput per thread = 1375881.50 KB/sec
Avg throughput per thread = 687940.75 KB/sec
Min xfer = 512.00 KB
Children see throughput for 2 readers = 2169601.25 KB/sec
Parent sees throughput for 2 readers = 27753.94 KB/sec
Min throughput per thread = 2169601.25 KB/sec
Max throughput per thread = 2169601.25 KB/sec
Avg throughput per thread = 1084800.62 KB/sec
Min xfer = 512.00 KB
Children see throughput for 2 re-readers = 2572435.25 KB/sec
Parent sees throughput for 2 re-readers = 26311.78 KB/sec
Min throughput per thread = 2572435.25 KB/sec
Max throughput per thread = 2572435.25 KB/sec
Avg throughput per thread = 1286217.62 KB/sec
Min xfer = 512.00 KB
iozone test complete.
我对“吞吐量”和“Min xfer”的含义感到困惑，有人可以帮助我吗？ 顺便问一下，为什么孩子和父母看到的吞吐量不同？谢谢！
I'm a new user of IOzone, when I run the IOzone with the command: ./iozone -i 0 -i 1 -t 2 -T, it generates the following result(partially):
Command line used: ./iozone -i 0 -i 1 -t 2 -T Output is in Kbytes/sec Time Resolution = 0.000001 seconds. Processor cache size set to 1024 Kbytes. Processor cache line size set to 32 bytes. File stride size set to 17 * record size. Throughput test with 2 threads Each thread writes a 512 Kbyte file in 4 Kbyte records
Children see throughput for 2 initial writers = 650943.69 KB/sec
Parent sees throughput for 2 initial writers = 13090.24 KB/sec
Min throughput per thread = 275299.72 KB/sec
Max throughput per thread = 375643.97 KB/sec
Avg throughput per thread = 325471.84 KB/sec
Min xfer = 356.00 KB
Children see throughput for 2 rewriters = 1375881.50 KB/sec
Parent sees throughput for 2 rewriters = 10523.74 KB/sec
Min throughput per thread = 1375881.50 KB/sec
Max throughput per thread = 1375881.50 KB/sec
Avg throughput per thread = 687940.75 KB/sec
Min xfer = 512.00 KB
Children see throughput for 2 readers = 2169601.25 KB/sec
Parent sees throughput for 2 readers = 27753.94 KB/sec
Min throughput per thread = 2169601.25 KB/sec
Max throughput per thread = 2169601.25 KB/sec
Avg throughput per thread = 1084800.62 KB/sec
Min xfer = 512.00 KB
Children see throughput for 2 re-readers = 2572435.25 KB/sec
Parent sees throughput for 2 re-readers = 26311.78 KB/sec
Min throughput per thread = 2572435.25 KB/sec
Max throughput per thread = 2572435.25 KB/sec
Avg throughput per thread = 1286217.62 KB/sec
Min xfer = 512.00 KB
iozone test complete.
I get confused about meaning of "throughput" and "Min xfer", is there someone can help me?
By the way, why the throughput seen from children and parent is different? Thanks!
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Min xfer是指一次写入的最小数据量。 “每个线程在 4 KB 记录中写入 512 KB 文件”
因此，如果 Min xfer 为 512.00 KB，它将立即将整个实际文件写入磁盘（将所有 4 KB 记录分组在一起）。
由于操作系统 I/O 缓冲，子级和父级吞吐量有所不同。 iozone 不会在吞吐量测试中强制直接（非缓冲）读取或写入。您真正测试的是系统的缓冲区缓存+磁盘缓存+磁盘速度组合。
Min xfer refers to the smallest amount of data written at one time. "Each thread writes a 512 Kbyte file in 4 Kbyte records"
So if the Min xfer was 512.00 KB it wrote the entire actual file to disk at once (grouped all the 4 Kbyte records together).
Children and parent throughput are different due to OS I/O buffering. iozone doesn't force direct (non-buffered) read or writes with the throughput test. What you're really testing is your system's buffer cache + disk cache + disk speed combo.