Groovy 中的类型转换

发布于 2024-12-07 10:06:03 字数 796 浏览 0 评论 0原文

我有两个问题。

我执行了以下代码来查找 $ 的 ASCII 值:

def a = "\$"
def b = (int)a 
println b //prints 36

嗯,我对答案很满意。但是当我尝试像这样反向执行时,我发现我遗漏了一些东西:

def a = 36
String b = a
println b // getting output only 36 

问题1:

所以我的第一个问题是为什么它打印 36 而为什么不打印 $ ?我这里错了吗?

好吧,如果相同的第一个代码块被重写为:

    def a = "\$"
    def b = a as int
    println b

如果我运行这个程序,我会得到这样的错误:

Caught: java.lang.NumberFormatException: For input string: "$"
    at T.run(T.groovy:2)

即使我试图做与以前相同的事情。我收到错误。

问题 2:

那么为什么 as 关键字在这里不起作用,并且 def a = (int)b 是否不等于到 <代码>def a = b as int?解释一下。

提前致谢。

I have two questions.

I did the following code to find the ASCII value of $ :

def a = "\$"
def b = (int)a 
println b //prints 36

Well I'm happy with the answer. But when I tried to do it in reverse like this, I found I'm missing something :

def a = 36
String b = a
println b // getting output only 36 

Question 1:

So my first question is why it prints 36 and why not $? Am I wrong here?

Well if the same first code block is re-written as:

    def a = "\$"
    def b = a as int
    println b

If I run this program I get an error like this :

Caught: java.lang.NumberFormatException: For input string: "$"
    at T.run(T.groovy:2)

Even though I'm trying to do the same as before. I'm getting an error.

Question 2:

So why does the as keyword doesn't work here and does def a = (int)b is not equal to to def a = b as int? Explain me.

Thanks in advance.

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心的憧憬 2024-12-14 10:06:03

当你将一个字符串转换为 int 时,只要其中有一个字符就可以了,所以我们可以说你将一个 char 转换为 int ,当你尝试将 int 转换为字符串时,我认为它使用了 toString 方法或类似的方法。尝试将 36 转换为 char,你会看到你的 '$'

when you cast a string to int it's ok while you have one char in it, so we can say you cast a char to int, when you try to cast int to a string i think it uses toString method or something like that. Try to cast 36 to char and you'll see your '$'

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