如何更改/确定 Flex 中函数执行的优先级?
所以基本上我有一个已调度事件的组件:
<components:MyComp id="Id" myDispatchedEvent(event)/>
在脚本标记中我有该函数:
private function myDispatchedEvent(event:Event):void
{
//Here I have my static function with title and handler function showConfirmation
Calculate.showConfirmation("String Title", function(event:Close):void
{
if(bla bla bla)
//lots of code etc. ...
});
//myDispatchEvent function continues here..
}
所以问题出在我的静态函数的 showConfirmation 处理程序上,如果我进行调试,它只会跳过该函数并继续执行 myDispatchedEvent。为什么 showConfirmation 函数中的匿名函数不执行?
谢谢
So basically I have a component with my event dispatched:
<components:MyComp id="Id" myDispatchedEvent(event)/>
In script tags I have that function:
private function myDispatchedEvent(event:Event):void
{
//Here I have my static function with title and handler function showConfirmation
Calculate.showConfirmation("String Title", function(event:Close):void
{
if(bla bla bla)
//lots of code etc. ...
});
//myDispatchEvent function continues here..
}
So problem is with my static function's showConfirmation handler, if I go through debug, it just skips that function and continues doing myDispatchedEvent. Why doesn't anonymous function inside showConfirmation function execute?
Thanks
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函数在调用时执行。就你而言,你只需声明它。在
Calculate.showConfirmation
内的某处调用此函数,它将被执行。像下面这样:
Functions are executing upon call. In your case you have just declaration of it. Call this function somewhere inside
Calculate.showConfirmation
and it will be executed.Something like the following:
首先我要说的是,你想做的事情很奇怪。我会尝试编写不同的解决方案,但这取决于您想要做什么。如果您告诉我们更多相关信息,我们可以找到更好的方法来实现您的目标。顺便说一句,你可以这样做:
类似于康斯坦丁已经告诉过你的事情。如果您不执行作为静态函数内的参数传递给静态函数的函数,则该函数将不会被执行。
Let me say first that what you're trying to do is quite strange. I'd try to code a different solution, but this depends on what you're trying to do. It you tell us a more about it we could find a better way to reach your goal. BTW, you can do something like this:
Something similar what Constantiner has already told you. If you don't execute the function that you're passing to your static function as a parameter inside this static function, it won't be executed.