As the analyzer says, you are allocating locs on line 647, using NSMutableArray *locs = [[NSMutableArray alloc] init]; and not releasing it later in the block. You should release it or you can use convenience constructor to get the autoreleased array like this, NSMutableArray *locs = [NSMutableArray array];
I'd suggest you to still simplify your code to this,
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正如分析器所说，您正在 647 行上分配 locs，使用
NSMutableArray *locs = [[NSMutableArray alloc] init];并且稍后不会在块中释放它。您应该释放它，或者您可以使用方便的构造函数来获取自动释放的数组，如下所示，NSMutableArray *locs = [NSMutableArray array];我建议您仍然简化您的对此的代码，
As the analyzer says, you are allocating locs on line 647, using
NSMutableArray *locs = [[NSMutableArray alloc] init];and not releasing it later in the block. You should release it or you can use convenience constructor to get the autoreleased array like this,NSMutableArray *locs = [NSMutableArray array];I'd suggest you to still simplify your code to this,
您需要在最后释放 locs。您已经分配并初始化了它，给它的引用计数为 1，然后您应该释放它以将引用计数更改为 0。请参阅 http://developer.apple.com/library/mac/documentation/Cocoa/Conceptual/MemoryMgmt/ 了解更多信息。
You need to release locs at the very end. You have alloc'ed and init'ed it, giving it a reference count of 1, an then you should release it to change the reference count to 0. Refer to http://developer.apple.com/library/mac/documentation/Cocoa/Conceptual/MemoryMgmt/ for more info.
您已经初始化了 locs 数组，然后必须在关闭该函数之前释放该数组：
[locs release];locs=nil;You have initialize the locs array then you have to release that array before closing that function:
[locs release];locs=nil;