在 Java 中使用 XML 发出 HTTPS Post 请求

Question

我正在尝试使用 Web Of Knowledge(WoK) 的 API 来获取一些数据。文档解释说您必须通过 HTTPS 执行 POST 请求，发送包含查询的 XML。但我只收到错误 400 表单服务器。 （错误的请求）

这是我的代码，我在谷歌中找到了它，我对我的情况做了一些修复。

public static void main(String[] args) throws Exception {



    // Get target URL
    String strURL = /*Here the Server URL*/;

    // Get file to be posted
    String strXMLFilename = "src/main/resources/xml/wosdata.xml";
    File input = new File(strXMLFilename);

    // Prepare HTTP post
    PostMethod post = new PostMethod(strURL);

    // Request content will be retrieved directly
    // from the input stream
    // Per default, the request content needs to be buffered
    // in order to determine its length.
    // Request body buffering can be avoided when
    // content length is explicitly specified
    post.setRequestEntity(new InputStreamRequestEntity(
            new FileInputStream(input), input.length()));

    // Specify content type and encoding
    // If content encoding is not explicitly specified
    // ISO-8859-1 is assumed
    post.setRequestHeader(
            "Content-type", "text/xml; charset=ISO-8859-1");

    // Get HTTP client
    HttpClient httpclient = new HttpClient();



    // Execute request
    try {

        int result = httpclient.executeMethod(post);

        // Display status code
        System.out.println("Response status code: " + result);

        // Display response
        System.out.println("Response body: ");
        System.out.println(post.getResponseBodyAsString());


    }catch (Exception e) {
        e.printStackTrace();

    } finally {
        // Release current connection to the connection pool 
        // once you are done
        post.releaseConnection();
    }
}

Answer 1

您发送的 XML 有问题。您必须查看服务器日志才能准确了解内容，因为 400 故意告诉您尽可能少的信息。

Answer 2

你应该这样做。首先将 xml 的内容读取到 String 并使用 StringRequestEntity 进行发布。

// Get file to be posted
String strXMLFilename = "src/main/resources/xml/wosdata.xml";
StringBuilder contents = new StringBuilder();

try {
  BufferedReader input =  new BufferedReader(new FileReader(new File(strXMLFilename)));
  try {
    while (( line = input.readLine()) != null){
      contents.append(line);
      contents.append(System.getProperty("line.separator"));
    }
  }
  finally {
    input.close();
  }



  StringEntity requestEntity = new StringEntity(contents.toString());
  post.setEntity(requestEntity);