DatagramPacket 接收到的附加字节
我有一个我第一次看到的问题，我正在使用 java DatagramSocket 在我的应用程序中发送和接收数据。
这就是我发送数据的方式：
byte[] buffer = "my data".getBytes();
senderPacket = new DatagramPacket(buffer, 0, buffer.length, remoteAddress, remotePort);
socket.send(senderPacket);
现在当我发送 byt[] 缓冲区时，它的大小是 275。 但是当我在接收应用程序上收到数据包并从receiverPacket 获取 byte[] 时，如下所示：
buffer = new byte[2048];
receiverPacket = new DatagramPacket(buffer, buffer.length);
socket.receive(receiverPacket);
我发现接收到的字节数为 278 个字节，即额外的 3 个字节。
这看起来似乎不是一个大问题，但实际上对我来说，请知道为什么会发生这种情况，以及如何解决它，任何合乎逻辑的解释都会有所帮助。
谢谢
I have a problem that I see for the first time ever, I'm using java DatagramSocket (s) for sending and receiving data in my app.
this is how I send the data:
byte[] buffer = "my data".getBytes();
senderPacket = new DatagramPacket(buffer, 0, buffer.length, remoteAddress, remotePort);
socket.send(senderPacket);
now when I sent the byt[] buffer, it's size was 275.
but when I received the packet on the receiving app and got the byte[] from the receiverPacket, like this:
buffer = new byte[2048];
receiverPacket = new DatagramPacket(buffer, buffer.length);
socket.receive(receiverPacket);
I found that the received bytes count where 278 bytes that's additional 3 bytes.
This might seem like not a big problem, but actually it is for me, please any idea why is this happening, and how to solve it, any logical explanation would be helpful.
thanks
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3 个额外字节可以是长度标记。我知道，当我在 C/C++ 中进行套接字时，我通常将前 4 个字节专用于发送消息的长度，然后使用该数据来确定要读取多少内容以读取整个消息。
The 3 extra bytes could be a length marker. I know that when I do sockets in C/C++, I typically dedicate the first 4 bytes to sending the length of my message, and then I use that data to determine how much to read in order to read the entire message.