如何通过行名称而不是数字索引删除矩阵的行？
我有矩阵 g：
> g[1:5,1:5]
rs7510853 rs10154488 rs12159982 rs2844887 rs2844888
NA06985 "CC" "CC" "CC" "CC" "CC"
NA06991 "CC" "CC" "CC" "CC" "CC"
NA06993 "CC" "CC" "CC" "CC" "CC"
NA06994 "CC" "CC" "CC" "CC" "CC"
NA07000 "CC" "CC" "CC" "CC" "CC"
> rownames(g)[1:2]->remove
> remove
[1] "NA06985" "NA06991"
> g[-remove,]
-remove 中的错误：一元运算符的参数无效
有没有一种简单的方法可以完成我在这里想做的事情（从矩阵 g 中删除向量“remove”中引用的 ID？
注意： 这只是我真正想做的事情的模型，请不要说只是做 g[-(1:2), ]，我需要能够删除我有一大堆行ID-d。
I have matrix g:
> g[1:5,1:5]
rs7510853 rs10154488 rs12159982 rs2844887 rs2844888
NA06985 "CC" "CC" "CC" "CC" "CC"
NA06991 "CC" "CC" "CC" "CC" "CC"
NA06993 "CC" "CC" "CC" "CC" "CC"
NA06994 "CC" "CC" "CC" "CC" "CC"
NA07000 "CC" "CC" "CC" "CC" "CC"
> rownames(g)[1:2]->remove
> remove
[1] "NA06985" "NA06991"
> g[-remove,]
Error in -remove : invalid argument to unary operator
Is there a simple way to do what I want to do here (remove the ID's referenced in the vector 'remove' from matrix g?
Note: this is just a model for what I actually want to do, please don't say just do g[-(1:2), ], I need to be able to remove a whole bunch of rows that I have ID-d.
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使用索引时，不能使用“负”字符向量。您可以使用 %in% 转换为逻辑
如果您确实想使用负索引，可以这样做：
...但是，当目标向量中没有任何行名时，它会产生令人讨厌的潜在错误结果。结果可能是没有返回任何值。
When working with indexing, you cannot use "negative" character vectors. You can convert to logical with %in%
If you really wanted to use negative-indexing this could be done:
... however it has a nasty potential erroneous result that arises when there are not any rownames in the target vector. The result may be no values returned.
索引时不能对字符向量进行负索引。将向量
remove转换为布尔值。我定义了一个函数，然后可以这样使用：
g[rownames(g) %notin% remove ,]You cannot negative index a character vector when indexing. Turn your vector
removeinto a boolean. I've defined a functionwhich can then be used as such:
g[rownames(g) %notin% remove ,]我使用“setdiff”如下：
I use "setdiff" as follows: