如何在 MySQL 中使用 GROUP BY(日期)从一周中的给定日期开始

发布于 2024-12-06 16:19:29 字数 278 浏览 1 评论 0原文

如果我有一个 MySQL 查询来按周汇总总数,例如:

select sum(keyword1), sum(keyword2), sum(keyword3), dateTime
from myTable
group by week(dateTime)
order by dateTime asc

我发现这些周似乎是从星期日开始的。

可以改成星期一吗?

列 dateTime 的格式为 MySQL 时间戳 2011-09-26 12:34:32。

If I have a MySQL query to aggregate totals by week, e.g.:

select sum(keyword1), sum(keyword2), sum(keyword3), dateTime
from myTable
group by week(dateTime)
order by dateTime asc

I find that the weeks appear to begin on a Sunday.

Can this be changed to a Monday?

Column dateTime is in MySQL Timestamp format 2011-09-26 12:34:32.

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评论(2

爱她像谁 2024-12-13 16:19:29

您希望星期日属于前一周,因此从中删除一天

select sum(keyword1), sum(keyword2), sum(keyword3),  week(DATE_SUB(dateTime, INTERVAL 1 DAY)) my_week
from myTable
group by week(DATE_SUB(dateTime, INTERVAL 1 DAY))
order by my_week asc

You want the sunday to belong to the previous week so remove one day from it

select sum(keyword1), sum(keyword2), sum(keyword3),  week(DATE_SUB(dateTime, INTERVAL 1 DAY)) my_week
from myTable
group by week(DATE_SUB(dateTime, INTERVAL 1 DAY))
order by my_week asc
陌伤ぢ 2024-12-13 16:19:29
mysql> select week('2011-09-25', 1);
+-----------------------+
| week('2011-09-25', 1) |
+-----------------------+
|                    38 |
+-----------------------+

mysql> select week('2011-09-25', 0);
+-----------------------+
| week('2011-09-25', 0) |
+-----------------------+
|                    39 |
+-----------------------+

所以, http://dev.mysql.com /doc/refman/5.5/en/server-system-variables.html#sysvar_default_week_format

mysql> select week('2011-09-25', 1);
+-----------------------+
| week('2011-09-25', 1) |
+-----------------------+
|                    38 |
+-----------------------+

mysql> select week('2011-09-25', 0);
+-----------------------+
| week('2011-09-25', 0) |
+-----------------------+
|                    39 |
+-----------------------+

So, http://dev.mysql.com/doc/refman/5.5/en/server-system-variables.html#sysvar_default_week_format

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