获取两个 NSDate 之间的所有日期（不是天数）

Question

如何获取两个日期之间的所有日期？

例如： 开始日期 = 2011/01/25 结束日期 = 2011/02/03

Answer 1

1）找出两个日期之间的天数。然后，

for(i=0;i<noofdays;i++)
{
//Find the next date
//add to the array
}

查找天数

查找下一个日期

Answer 2

NSCalendarUnit 用于定义日期和时间之间的步长。处理日期的标准化。

iOS 8 API、Swift 2.0

    func generateDates(calendarUnit: NSCalendarUnit, startDate: NSDate, endDate: NSDate) -> [NSDate] {

            let calendar = NSCalendar.currentCalendar()
            let normalizedStartDate = calendar.startOfDayForDate(startDate)
            let normalizedEndDate = calendar.startOfDayForDate(endDate)

            var dates = [normalizedStartDate]
            var currentDate = normalizedStartDate

            repeat {

                currentDate = calendar.dateByAddingUnit(calendarUnit, value: 1, toDate: currentDate, options: NSCalendarOptions.MatchNextTime)!
                dates.append(currentDate)

            } while !calendar.isDate(currentDate, inSameDayAsDate: normalizedEndDate)

            return dates
    }

Answer 3

要查找两个 NSDate 之间的所有日期：

- (void)cerateDaysArray{
    _daysArray = [NSMutableArray new];
    NSCalendar *calendar = [[NSCalendaralloc]initWithCalendarIdentifier:NSGregorianCalendar];
    [calendar setTimeZone:[NSTimeZone systemTimeZone]];
    NSDate *startDate = [_minDate copy];
    NSDateComponents *deltaDays = [NSDateComponents new];
    [deltaDays setDay:1];
    [_daysArray addObject:startDate];
    while ([startDate compare:_maxDate] == NSOrderedAscending) {
       startDate = [calendar dateByAddingComponents:deltaDays toDate:startDate options:0];
       [_daysArray addObject:startDate];
   }
}