WCF 日期时间到 NSDate

发布于 2024-12-06 12:44:31 字数 799 浏览 0 评论 0原文

我正在使用返回 JSON WCF DateTime 的 Web 服务。

该字符串类似于 \/Date(1316397792913+0800)\/

我有兴趣提取 1316397792 这是自 1970 年 1 月 1 日以来的时间（以秒为单位）。这样我就可以使用 NSDate timeIntervalSince1970 方法来获取当前时间。我剪掉了最后 3 位数字，因为它以毫秒为单位，而 timeIntervalSince1970 以秒为单位。

这是我目前正在做的事情，它不适用于 2001 年之前的某个日期，该日期自 1970 年以来的时间间隔（以毫秒为单位）少于 10 个字符。

NSString *dateString = @"\/Date(1316397792913+0800)\/";
    NSLog(@"dateString :%@", dateString);

    NSDate *date = [NSDate dateWithTimeIntervalSince1970:
                    [[dateString substringWithRange:NSMakeRange(6, 10)] intValue]];
    NSLog(@"NSDate:%@", date);

dateString :/Date(1316397792913+0800)/
NSDate:2011-09-19 02:03:12 +0000

因此，我需要更好地处理 dateString，它并不假设每次我们都会获取 10 个字符。

原文

I am using a web services which returns a JSON WCF DateTime.

The string goes like \/Date(1316397792913+0800)\/

I am interested in extracting out the 1316397792 which is the time since 1st Jan 1970 in seconds. So that I can use the NSDate timeIntervalSince1970 method to get the present time. I cropped out the last 3 digits as it's in milliseconds and the timeIntervalSince1970 takes in seconds.

Here's what I am currently doing which does not work for dates somewhere before 2001 which has a time interval in ms since 1970 less than 10 characters.

NSString *dateString = @"\/Date(1316397792913+0800)\/";
    NSLog(@"dateString :%@", dateString);

    NSDate *date = [NSDate dateWithTimeIntervalSince1970:
                    [[dateString substringWithRange:NSMakeRange(6, 10)] intValue]];
    NSLog(@"NSDate:%@", date);

dateString :/Date(1316397792913+0800)/
NSDate:2011-09-19 02:03:12 +0000

Therefore, I need a better work around playing with the dateString which does not assume everytime we will be feteching 10 characters.

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土豪 2024-12-13 12:44:31

您可以简单地获取 ( 索引和 + 索引之间的子字符串。类似于：

NSRange begin = [dateString rangeOfString:"("];
NSRange end = [dateString rangeOfString:"+"];
NSString* milliSecondsSince1970 = [dateString substringWithRange:NSMakeRange(begin.location + 1, end.location - begin.location - 1)];

PS：检查一次性错误。

You can simply get the substring between the index of ( and the index of +. Something like:

NSRange begin = [dateString rangeOfString:"("];
NSRange end = [dateString rangeOfString:"+"];
NSString* milliSecondsSince1970 = [dateString substringWithRange:NSMakeRange(begin.location + 1, end.location - begin.location - 1)];

P.S: Check for the one off error.

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