将方法的返回公开到属性中

Question

如何将我的方法的返回公开到类属性中？

public class BIContactLib: ContactLib
{

   //Expose it here.. to replace the code below

    public IEnumerable<BIContactLib> GetContactLibs 
    {
        get { return (BIContactLib) GetAll}
        set { ; }
    }
}

public class BIContactLibService : IBIRequirement, IDisposable
{
    private ClientContext context = new ClientContext();

  //The return of the method here is the one I would like to expose

    public IEnumerable<BIContactLib> GetAll()
    {
        var contactslib = context.ContactLibs;
        return contactslib.ToList();
    }
}

这背后的原因是我想创建一个包含联系人库列表的视图模型...顺便说一句，这是我的视图模型..

public class PersonInformation
{
    public BIPerson Person { get; set; }
    public BIAddress Address { get; set; }

    //This is where i want to use it

    public IEnumerable<BIContactLib> GetAll { get; set; }
}

或者有其他方法可以做到这一点？

此致，

Answer 1

像这样的事情怎么样

public IEnumerable<BIContactLib> GetContactLibs 
    {
        get { 
             BiContractLib lib = new BiContractLib();
             return lib.GetAll();
            }        
    }