android：ksoap2 org.xmlpull.v1.XmlPullParserException：预期：START_TAG异常

发布于 2024-12-06 11:08:27 字数 2302 浏览 1 评论 0原文

我正在尝试从网络服务获取响应。但是我遇到了一些异常错误：主要是这个错误

org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <html>@1:6 in java.io.InputStreamReader@40524b78)

实际上我正在尝试访问 Web 服务的一种方法，并且 Web 服务应该返回两个字符串（比如说 String1 和 String2）。此外，我必须提供或传递两个参数（假设参数 1 和参数 2，其中参数 1 应该是整数，参数 2 应该是字符串）这是我的代码

public class MyWebService extends Activity {

private static final String SOAP_ACTION ="http://www.mywebsite.com/myMethod";
private static final String METHOD_NAME = "MyMethod";
private static final String NAMESPACE = "http://www.myNamespace/";
    private static final String URL = "http://mysession.com/myservice.asmx?WSDL";


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    try {
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

        PropertyInfo pi = new PropertyInfo();   
        pi.setName("Parameter 1");
        pi.setValue(1);
        pi.setType(pi.INTEGER_CLASS);
        request.addProperty(pi);

        PropertyInfo pi2 = new PropertyInfo();  
        pi2.setName("Parameter 2");
        pi2.setValue("Any string");
        pi2.setType(pi2.STRING_CLASS);
        request.addProperty(pi2);

        SoapSerializationEnvelope envelope = new  SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
        androidHttpTransport.call(SOAP_ACTION, envelope);                   
        //SoapObject result=(SoapObject)envelope.getResponse();             
        SoapPrimitive  result = (SoapPrimitive) envelope.getResponse();
        String resultData = result.toString();

        //String string1=result.getProperty(0).toString();
        //String string2=result.getProperty(1).toString();

        Log.v("WEBSERVICE","RESPONSE: "+resultData);
    } catch (Exception e) {
        e.printStackTrace();    

    }        
}

}

任何人都可以告诉我我在这里是否做错了什么。非常重要的问题：谁能告诉我为什么我不能将 getProperty(0) 或 getProperty(1) 方法与此处的结果一起使用。我应该从 webservice 获得两个字符串作为响应，但我不能将 getProperty(index) 与 SoapPrimitive 一起使用。感谢所有建议谢谢

原文

I am trying to get a response from a web service. However I am getting some exception errors: mainly this one

org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <html>@1:6 in java.io.InputStreamReader@40524b78)

Actually I am trying to access a method of a web-service and the webservice is supposed to return two strings (Lets say String1 and String2). Moreover, I have to provide or pass two parameters (lets say Parameter 1 and Parameter 2 where Parameter 1 should be integer and Parameter 2 should be String) Here is my code

public class MyWebService extends Activity {

private static final String SOAP_ACTION ="http://www.mywebsite.com/myMethod";
private static final String METHOD_NAME = "MyMethod";
private static final String NAMESPACE = "http://www.myNamespace/";
    private static final String URL = "http://mysession.com/myservice.asmx?WSDL";


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    try {
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

        PropertyInfo pi = new PropertyInfo();   
        pi.setName("Parameter 1");
        pi.setValue(1);
        pi.setType(pi.INTEGER_CLASS);
        request.addProperty(pi);

        PropertyInfo pi2 = new PropertyInfo();  
        pi2.setName("Parameter 2");
        pi2.setValue("Any string");
        pi2.setType(pi2.STRING_CLASS);
        request.addProperty(pi2);

        SoapSerializationEnvelope envelope = new  SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
        androidHttpTransport.call(SOAP_ACTION, envelope);                   
        //SoapObject result=(SoapObject)envelope.getResponse();             
        SoapPrimitive  result = (SoapPrimitive) envelope.getResponse();
        String resultData = result.toString();

        //String string1=result.getProperty(0).toString();
        //String string2=result.getProperty(1).toString();

        Log.v("WEBSERVICE","RESPONSE: "+resultData);
    } catch (Exception e) {
        e.printStackTrace();    

    }        
}

}

Can anyone tell me if I am doing something wrong here.. Another very important question:
Can anyone tell me that why I can't use getProperty(0) or getProperty(1) method with the result here. I am supposed to get two strings in response from webservice but I can't use getProperty(index) with SoapPrimitive..
All suggestions are appreciated
Thanks

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莫多说 2024-12-13 11:08:27

我不确定这是否是您需要的确切解决方案，但这对我有用，我之前遇到过同样的问题，但是需要 5 个参数，我只是使用 SoapObject 添加了 3 个参数，所以它给出了这种类型的错误，所以请在调用此 Web 服务之前，请确保您已使用 request.addProperty("test","test") 添加了所有必需的参数。

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