Zend Ajax 实施后

发布于 2024-12-06 06:43:30 字数 861 浏览 0 评论 0原文

我有一个带有选项的选择下拉列表：

<select id="select_privilege_section" name="select_privilege_section" onchange="">
    <option value="pages">Pages</option> 
    <option value="forms">Forms</option> 
    <option value="roles">Roles</option> 
    <option value="cos">Change of Status</option>
</select>

我需要能够通过ajax将更改时选择的选项发送到要在那里检索的控制器中的特定操作，以便选择与必须显示的选项相关的表单：

var input =  $(this).val();

$.ajax ({
    type: "POST",
    url: location.protocol + '//' + location.host + '/role/privilege/format/html',
    data: {"form": input},
    success: function(data) {
    console.log("Success!!");   
  } 
});

但我无法获得 $_POST['form']; 知道

为什么吗？

先感谢您！

原文

I have a select dropdown with options:

<select id="select_privilege_section" name="select_privilege_section" onchange="">
    <option value="pages">Pages</option> 
    <option value="forms">Forms</option> 
    <option value="roles">Roles</option> 
    <option value="cos">Change of Status</option>
</select>

I need to be able to send via ajax the option selected on change, to a specific action in a controller to be retrieved there in order to select which form related to the option it has to be displayed:

var input =  $(this).val();

$.ajax ({
    type: "POST",
    url: location.protocol + '//' + location.host + '/role/privilege/format/html',
    data: {"form": input},
    success: function(data) {
    console.log("Success!!");   
  } 
});

But I am not being able to get the $_POST['form']; there

Any idea why?

thank you in advance!

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