PHP COUNT_RECURSIVE 只计算非数组值？

Question

我有一个多维数组，其调整为 $doclist['area']['source'][#]['type']

我想获取 的所有条目的数量['type'] = "title" 不为空。

有简单的方法吗？

当我这样做时，有没有办法获取 ['type'] = "title" AND ['area'] = "something" 的所有条目的数量> 不为空？

Answer 1

假设 'area' 和 'source' 你指的是任意字符串，你可以嵌套几个循环，如下所示：

$num_titles = 0;
foreach ($doclist as $area => $arr1) {
    foreach ($arr1 as $source => $arr2) {
        foreach ($arr2 as $k => $arr3) {
            if (isset($arr3['title']) && strlen(trim($arr3['title'])))
                $num_titles++;
        }
    }
}
print "Titles: {$num_titles}\n";
print "Areas: " . sizeof($doclist) . "\n";

Answer 2

这是我根据 rfausak 的回复编写的函数：

function countdocs($arr,$x="",$y="") {
        if (($x) && ($y)) {
            return count($arr[$x][$y]);
        } else if ($x) {
            $r=0;
            foreach ($arr[$x] as $arr1) {
                $r+=count($arr1);
            }
            return $r;
        } else {
            $r=0;
            foreach ($arr as $arr1) {
                foreach ($arr1 as $arr2) {
                    $r+=count($arr2);
                }
            }
            return $r;
        }
    }

我认为有人可能会发现它有用。

Answer 3

$ships = array(
    "Passenger ship" =>
        array("Yacht", "Liner", "Ferry"),
    "War ship" =>
        array("Battle-wagon", "Submarine", "Cruiser"),
    "Freight ship" =>
        array("Tank vessel", "Dry-cargo ship", "Container
      cargo ship")
);

function myCount($var, $i = 0){
    $cnt = 0;
    foreach ($var as $v) {
        if (is_array($v) and $i)
            $cnt += myCount($v, 0);
        $cnt++;
    }
    return $cnt;
}
echo myCount($ships, 1);