使用 QtDesigner 的 pyQt 信号/槽
我正在尝试编写一个与 QGraphicsView 交互的程序。我想在 QGraphicsView 中发生事件时收集鼠标和键盘事件。例如,如果用户单击 QGraphicsView 小部件,我将获得鼠标位置,类似的东西。我可以很容易地对其进行硬编码,但我想使用 QtDesigner,因为 UI 会经常更改。
这是我的 gui.py 代码。一个简单的小部件,其中包含 QGraphicsView。
from PyQt4 import QtCore, QtGui
try:
_fromUtf8 = QtCore.QString.fromUtf8
except AttributeError:
_fromUtf8 = lambda s: s
class Ui_graphicsViewWidget(object):
def setupUi(self, graphicsViewWidget):
graphicsViewWidget.setObjectName(_fromUtf8("graphicsViewWidget"))
graphicsViewWidget.resize(400, 300)
graphicsViewWidget.setMouseTracking(True)
self.graphicsView = QtGui.QGraphicsView(graphicsViewWidget)
self.graphicsView.setGeometry(QtCore.QRect(70, 40, 256, 192))
self.graphicsView.setObjectName(_fromUtf8("graphicsView"))
self.retranslateUi(graphicsViewWidget)
QtCore.QMetaObject.connectSlotsByName(graphicsViewWidget)
def retranslateUi(self, graphicsViewWidget):
graphicsViewWidget.setWindowTitle(QtGui.QApplication.translate("graphicsViewWidget", "Form", None, QtGui.QApplication.UnicodeUTF8))
该程序的代码:
#!/usr/bin/python -d
import sys
from PyQt4 import QtCore, QtGui
from gui import Ui_graphicsViewWidget
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_graphicsViewWidget()
self.ui.setupUi(self)
QtCore.QObject.connect(self.ui.graphicsView, QtCore.SIGNAL("moved"), self.test)
def mouseMoveEvent(self, event):
print "Mouse Pointer is currently hovering at: ", event.pos()
self.emit(QtCore.SIGNAL("moved"), event)
def test(self, event):
print('in test')
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MyForm()
myapp.show()
sys.exit(app.exec_())
当我运行此代码时,它给出的结果与我想要的相反。除了 QGraphicsView 内部之外,我在任何地方都可以获取鼠标位置。
我确定这是我的 QObject.connect 的问题。但每次我回去阅读有关信号和槽的内容时,它都是有道理的,但我无法理解。
请大家帮帮忙,我这几天一直头疼。如果之前有人问过这个问题,我很抱歉,但我已经浏览了有关该主题的所有线程,但我无法得到任何结果。
谢谢
I'm trying to write a program that will interact with QGraphicsView. I want to gather mouse and keyboard events when the happen in the QGraphicsView. For example, if the user clicks on the QGraphicsView widget I will get the mouse position, something like that. I can hard code it rather easily, but I want to use QtDesigner because the UI will be changing frequently.
This is the code that I have for the gui.py. A simple widget with a QGraphicsView in it.
from PyQt4 import QtCore, QtGui
try:
_fromUtf8 = QtCore.QString.fromUtf8
except AttributeError:
_fromUtf8 = lambda s: s
class Ui_graphicsViewWidget(object):
def setupUi(self, graphicsViewWidget):
graphicsViewWidget.setObjectName(_fromUtf8("graphicsViewWidget"))
graphicsViewWidget.resize(400, 300)
graphicsViewWidget.setMouseTracking(True)
self.graphicsView = QtGui.QGraphicsView(graphicsViewWidget)
self.graphicsView.setGeometry(QtCore.QRect(70, 40, 256, 192))
self.graphicsView.setObjectName(_fromUtf8("graphicsView"))
self.retranslateUi(graphicsViewWidget)
QtCore.QMetaObject.connectSlotsByName(graphicsViewWidget)
def retranslateUi(self, graphicsViewWidget):
graphicsViewWidget.setWindowTitle(QtGui.QApplication.translate("graphicsViewWidget", "Form", None, QtGui.QApplication.UnicodeUTF8))
The code for the program:
#!/usr/bin/python -d
import sys
from PyQt4 import QtCore, QtGui
from gui import Ui_graphicsViewWidget
class MyForm(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_graphicsViewWidget()
self.ui.setupUi(self)
QtCore.QObject.connect(self.ui.graphicsView, QtCore.SIGNAL("moved"), self.test)
def mouseMoveEvent(self, event):
print "Mouse Pointer is currently hovering at: ", event.pos()
self.emit(QtCore.SIGNAL("moved"), event)
def test(self, event):
print('in test')
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MyForm()
myapp.show()
sys.exit(app.exec_())
When I run this code, it gives me the opposite of what I want. I get the mouse position everywhere except for inside the QGraphicsView.
I'm sure it's a problem with my QObject.connect. But every time I go back and read about signals and slots it makes sense but I can't get it.
Please help, I've been banging my head for the past few days now. I'm sorry if this as been asked before but I've been through all the threads on this topic and I can't get anywhere.
Thanks
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信号必须来自 ui 中定义的 QGraphicsView 对象。
您可以像这样创建一个从
QGraphicsView
派生的类然后,在设计器中:
QGraphicsView
然后Promote to您可以使用 pyuic4 重新生成文件 gui.py。
The signal must come from the
QGraphicsView
object that was defined in the ui.You can create a class derived from
QGraphicsView
like thisThen, in the designer:
QGraphicsView
then Promote toAnd you can regenerate your file gui.py with pyuic4.