将 const double[][] 数组作为参数传递给 double** 接口
我有一个 2 维常量双矩阵，需要将其作为参数传递给采用（非常量）双**参数的函数。
[CEqParams.h] // < given as is - can't do a thing about it
class CEqParams
{
public:
void operator=(const CEqParams &right);
...
double dm_params[4][8];
};
。
[some_functions.h] // < dto.
...
void setEqParams(double **m);
...
。
[CEqParams.cpp]
void CEqParams::operator=(const CEqParams &right)
{
setEqParams( « magic here » );
}
其中« magic here »（在代码片段的最后一段中）应采用right.dm_params（或其内容的适当表示）。
除了手动将 right.dm_params 传输到辅助 double** 结构（通过运行在所有数组字段上的嵌套循环并逐一复制它们）然后还有什么其他方法吗？我可以在这里将后者传递给 setEqParams 吗？
PS：假设我能够将 right.dm_params 传递给采用 double[][] （或 double[4][8 ]？）作为参数 - 我如何摆脱 const？ “提示”：const_cast 不起作用。
I have a 2-dim const double matrix which needs to be passed as argument to a function that takes a (non-const) double** parameter.
[CEqParams.h] // < given as is - can't do a thing about it
class CEqParams
{
public:
void operator=(const CEqParams &right);
...
double dm_params[4][8];
};
.
[some_functions.h] // < dto.
...
void setEqParams(double **m);
...
.
[CEqParams.cpp]
void CEqParams::operator=(const CEqParams &right)
{
setEqParams( « magic here » );
}
where « magic here » (in the final segment of code snippets) shall take right.dm_params (or an appropriate representation of its contents, respectively).
What else than manually transferring right.dm_params to an auxiliary double** structure (by means of a nested loop running over all array fields and copying them one by one) and then passing the latter to setEqParams could I do here?
PS: And given I'd be able to pass right.dm_params to a function that takes a double[][] (or double[4][8]?) as parameter - how would I get rid of the const? "Hint": A const_cast<double[4][8]>(right.dm_parameters) doesn't work.
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一种相当丑陋的方法，至少不需要复制所有数据，是创建一个行指针的临时数组，例如
One fairly ugly way, which at least doesn't require duplicating all the data, is to create a temporary array of row pointers, e.g.