如果变量中存在某个字符，则将字符附加到变量中？

发布于 2024-12-06 03:27:15 字数 258 浏览 0 评论 0原文

我将如何进行以下 also 检查 $word 的最后一个字符是否等于“h”，如果为真，则附加“es”？对“h”的检查将在对“s”的检查之前进行，如果为真，则无需检查“s”。

<?php

$word = "watch";

$newword = "$word".(substr($word, -1)=="s"?"":"s")." is the new word";

echo $newword;

?>

原文

How would I go about making the following also check if the last character of $word is equal to "h" if true then append "es"? This check for "h" would be before the check for "s" and if true there would be no need to check for "s".

<?php

$word = "watch";

$newword = "$word".(substr($word, -1)=="s"?"":"s")." is the new word";

echo $newword;

?>

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时光是把杀猪刀 2024-12-13 03:27:15

switch (substr($word, -1)) {
    case 'h':
        $newword = $word . 'es';
        break;
    case 's':
        $newword = $word;
        break;
    default:
        $newword = $word;
}

或其某种变体。如果您尝试使单词复数，已经有很多解决方案，例如：复数方法

switch (substr($word, -1)) {
    case 'h':
        $newword = $word . 'es';
        break;
    case 's':
        $newword = $word;
        break;
    default:
        $newword = $word;
}

Or some variation thereof. If you are trying to pluralize words, there are already a number of solutions, for example: pluralize method

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