Objective-C：帮助我将时间戳转换为格式化的日期/时间

发布于 2024-12-06 03:25:37 字数 659 浏览 1 评论 0原文

我真的很难将此时间戳转换为格式良好的日期字符串。

这是时间戳：“1316625985”

这是我所做的函数：

-(NSString*)timestamp2date:(NSString*)timestamp{
    NSString * timeStampString =timestamp;
    //[timeStampString stringByAppendingString:@"000"];   //convert to ms
    NSTimeInterval _interval=[timeStampString doubleValue];
    NSDate *date = [NSDate dateWithTimeIntervalSince1970:_interval];
    NSDateFormatter *_formatter=[[NSDateFormatter alloc]init];
    [_formatter setDateFormat:@"dd/MM/yy"];
    return [_formatter stringFromDate:date];
}

问题是，它一直返回 1972 年的日期！ (31/7/72) 这是错误的，因为它是 2011 年 9 月的日期...

任何人都可以提出任何解决方案吗？

预先非常感谢，

原文

I'm really struggling to convert this timestamp to a nice formatted date string.

Here's the timestamp: "1316625985"

And here's the function I've made:

-(NSString*)timestamp2date:(NSString*)timestamp{
    NSString * timeStampString =timestamp;
    //[timeStampString stringByAppendingString:@"000"];   //convert to ms
    NSTimeInterval _interval=[timeStampString doubleValue];
    NSDate *date = [NSDate dateWithTimeIntervalSince1970:_interval];
    NSDateFormatter *_formatter=[[NSDateFormatter alloc]init];
    [_formatter setDateFormat:@"dd/MM/yy"];
    return [_formatter stringFromDate:date];
}

Trouble is, it keeps returning dates in 1972! (31/7/72) This is wrong, since it's a September 2011 date...

Can anyone suggest any solution?

Many thanks in advance,

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

‖放下 2024-12-13 03:25:37

纪元不是自 1970 年 1 月 1 日以来的秒吗？你确定你没有留下毫秒行吗？

当我运行你的逻辑时（没有你的行附加 000 毫秒），它起作用了。这就是我所做的：

    NSString * timeStampString = @"1316641549";
    NSTimeInterval _interval=[timeStampString doubleValue];
    NSDate *date = [NSDate dateWithTimeIntervalSince1970:_interval];
    NSLog(@"%@", date);

它输出：

2011-09-21 17:46:14.384 Craplet[13218:707] 2011-09-21 21:45:49 +0000

Isn't epoch seconds since 1/1/1970? are you sure that you didn't leave the millisecond line in?

When I ran you're logic (without your line append 000 for ms), it worked. Here's what I did:

    NSString * timeStampString = @"1316641549";
    NSTimeInterval _interval=[timeStampString doubleValue];
    NSDate *date = [NSDate dateWithTimeIntervalSince1970:_interval];
    NSLog(@"%@", date);

It outputted:

2011-09-21 17:46:14.384 Craplet[13218:707] 2011-09-21 21:45:49 +0000

回复收藏 0 原文

吹梦到西洲 2024-12-13 03:25:37

只需将 [timeStampString doubleValue] 除以一千即可：

NSDate *date = [NSDate dateWithTimeIntervalSince1970:[timeStampString doubleValue]/1000.0];
NSDateFormatter *_formatter=[[NSDateFormatter alloc]init];
[_formatter setDateFormat:@"dd/MM/yy"];
return [_formatter stringFromDate:date];

或者尝试 [timeStampString longLongValue]/1000.0 祝

你好运！

Just divide your [timeStampString doubleValue] by a thousand like:

NSDate *date = [NSDate dateWithTimeIntervalSince1970:[timeStampString doubleValue]/1000.0];
NSDateFormatter *_formatter=[[NSDateFormatter alloc]init];
[_formatter setDateFormat:@"dd/MM/yy"];
return [_formatter stringFromDate:date];

or try [timeStampString longLongValue]/1000.0 instead

Good Luck!

回复收藏 0 原文