如何通过 linq 访问 XML 节点上的属性？

发布于 2024-12-05 22:24:48 字数 791 浏览 1 评论 0原文

我通读了这个邮政。

我有这个 XML：

<?xml version="1.0" encoding="utf-8" ?>
    <Export version="" srcSys="" dstSys="" srcDatabase="" timeStamp="">

    </Export>

这是我尝试过的，但没有运气：

var xml = XElement.Parse(BuyingModule.Properties.Resources.Export);

Func<XElement, string, string> GetAttribute = (e, property) => e.Elements("property").Where(p => p.Attribute("name").Value == property).Single().Value;

var query = from record in xml.Elements("Export")
            select record;

var prop = GetAttribute(query.FirstOrDefault(), "version");

如何访问“导出”节点的属性？

我需要设置这些属性

原文

I read through this post.

I have this XML:

<?xml version="1.0" encoding="utf-8" ?>
    <Export version="" srcSys="" dstSys="" srcDatabase="" timeStamp="">

    </Export>

This is what i tried, but with no luck:

var xml = XElement.Parse(BuyingModule.Properties.Resources.Export);

Func<XElement, string, string> GetAttribute = (e, property) => e.Elements("property").Where(p => p.Attribute("name").Value == property).Single().Value;

var query = from record in xml.Elements("Export")
            select record;

var prop = GetAttribute(query.FirstOrDefault(), "version");

How do i access to properties of the "Export" Node?

I need to set those properties

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信仰 2024-12-12 22:24:48

Export 元素没有 properties 元素，而这正是您的 GetAttribute 方法尝试查找的内容。

我的猜测是您实际上想要：

var element = xml.Element("Export"); // Just get the first element
var version = (string) element.Attribute("version");

我不清楚为什么您在这里使用查询表达式和委托 - 这只是比您需要的更复杂的事情。但是属性(XName) 可能是您所缺少的......

The Export element doesn't have a properties element, which is what your GetAttribute method is trying to find.

My guess is you actually want:

var element = xml.Element("Export"); // Just get the first element
var version = (string) element.Attribute("version");

It's not clear to me why you've used a query expression and a delegate here - it's just things more complicated than you need. But Attribute(XName) is probably what you were missing...

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