如何通过 Service 内的 BroadcastReceiver 接收操作

发布于 2024-12-05 21:21:06 字数 1169 浏览 0 评论 0原文

我在接收小部件作为 PendingIntent 发送的意图时遇到问题：

intent = new Intent(MyService.MY_ACTION);
pendingIntent = PendingIntent.getService(this, 0, intent, 0);
views.setOnClickPendingIntent(R.id.button, pendingIntent);

我向 MyService 添加了一个广播接收器：

private BroadcastReceiver mIntentReceiver = new BroadcastReceiver()
{
    @Override
    public void onReceive(Context context, Intent intent) 
    {
        Log.d(TAG, "Intent command received");
        String action = intent.getAction();

        if( MY_ACTION.equals(action))
        {
            doSomeAction();
        }
    }
};

最后我在服务的 onCreate 方法中注册了这个接收器：

IntentFilter filter = new IntentFilter();
filter.addAction(MY_ACTION);
registerReceiver(mIntentReceiver, filter);

现在当 MyService 正在运行并且我单击按钮时，我得到：

09-21 14:21:18.723: WARN/ActivityManager(59): Unable to start service Intent { act=com.myapp.MyService.MY_ACTION flg=0x10000000 bnds=[31,280][71,317] }: not found

我还尝试将意图过滤器（使用 MY_ACTION 操作）添加到 MyService 的清单文件中，但它会导致调用 MyService 的 onStartCommand 方法。这不是我想要的。我需要调用mIntentReceiver的onReceive方法。

原文

I have problem with receiving an intent sended by widget as PendingIntent:

intent = new Intent(MyService.MY_ACTION);
pendingIntent = PendingIntent.getService(this, 0, intent, 0);
views.setOnClickPendingIntent(R.id.button, pendingIntent);

I added a broadcast receiver to MyService:

private BroadcastReceiver mIntentReceiver = new BroadcastReceiver()
{
    @Override
    public void onReceive(Context context, Intent intent) 
    {
        Log.d(TAG, "Intent command received");
        String action = intent.getAction();

        if( MY_ACTION.equals(action))
        {
            doSomeAction();
        }
    }
};

and finally I registered this receiver i onCreate method of the service:

IntentFilter filter = new IntentFilter();
filter.addAction(MY_ACTION);
registerReceiver(mIntentReceiver, filter);

And now when th MyService is running and I click the button, I get :

09-21 14:21:18.723: WARN/ActivityManager(59): Unable to start service Intent { act=com.myapp.MyService.MY_ACTION flg=0x10000000 bnds=[31,280][71,317] }: not found

I also tried to add an intent-filter (with MY_ACTION action) to manifest file to MyService but it causes calling onStartCommand method of MyService. And that is not what I want. I need to call the onReceive method of mIntentReceiver.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

迎风吟唱 2024-12-12 21:21:07

你想让我做什么？

如果您在 Service onCreate 方法中注册广播接收器，则：

您应该引发广播意图，而不是服务意图。更改此：
pendingIntent = PendingIntent.getService(this, 0, Intent, 0);

为此：

pendingIntent = PendingIntent.getBroadcast(this, 0, intent, 0);

您的服务应该正在运行来侦听此广播事件，这不会运行您的服务，因为您在创建服务时正在注册接收器。

What do you want to do?

If you register a broadcast receiver in your Service onCreate method then:

You should raise a broadcast intent, not a service intent. Change this:
pendingIntent = PendingIntent.getService(this, 0, intent, 0);

To this:

pendingIntent = PendingIntent.getBroadcast(this, 0, intent, 0);

You service should be running to listen for this broadcast event, this will not run your service, since you are registering the receiver when the service is created.

回复收藏 0 原文