使用 Zend Router 提供对 Seo 友好的 url

发布于 2024-12-05 17:27:44 字数 291 浏览 0 评论 0原文

我想在我的 Zend Framework 应用程序中创建 seo 友好的 url，但是正确的语法是怎样的：

$newsroute = new Zend_Controller_Router_Route(
   'news/:action/:id_:title',
    array( 'controller' => 'news' ));

:id_:title 显然不起作用，因为 Zend 不知道 _ 是分隔符？我是否需要使用正则表达式路由器来实现此目的，或者它也可以与普通路由器一起使用吗？

原文

I want to create seo friendly urls in my Zend Framework application but how is the correct syntax for this:

$newsroute = new Zend_Controller_Router_Route(
   'news/:action/:id_:title',
    array( 'controller' => 'news' ));

:id_:title obviously doesn't work since Zend didn't know that _ is a separator? Do i need to use the regex router for this or does it work with the normal one too?

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南风起 2024-12-12 17:27:44

事实上，正则表达式路线就可以做到这一点。

如果出于某种原因您不想使用正则表达式路由，可以通过前端控制器插件实现一个简单的解决方法：

//replace the :id and :title params with a single one, mapping them both
$newsroute = new Zend_Controller_Router_Route(
        'news/:action/:article',
         array( 'controller' => 'news' )
   );

// in a front controller plugin, you extract the Id form the article param
function function dispatchLoopStartup( Zend_Controller_Request_Abstract $request ) {

    if( $request->getParam( 'article', false ) ){

        $slug = $request->getParam( 'article' );
        $parts = array();
        preg_match( '/^(\d+)/', $slug, $parts );

        // add the extracted id to the request as if there where an :id param
        $request->setParam( 'id', $parts[0] );
    } 
}

当然，如果需要，您也可以以相同的方式提取标题。

当你想生成 url 时，不要忘记构建你的 'article' 参数：

 $this->url( array( 'article' => $id.'_'.$title ) );

Indeed a regex route would do the thing.

If for any reason you don't want to use the regex route, there is a simple workaround via a front controller plugin:

//replace the :id and :title params with a single one, mapping them both
$newsroute = new Zend_Controller_Router_Route(
        'news/:action/:article',
         array( 'controller' => 'news' )
   );

// in a front controller plugin, you extract the Id form the article param
function function dispatchLoopStartup( Zend_Controller_Request_Abstract $request ) {

    if( $request->getParam( 'article', false ) ){

        $slug = $request->getParam( 'article' );
        $parts = array();
        preg_match( '/^(\d+)/', $slug, $parts );

        // add the extracted id to the request as if there where an :id param
        $request->setParam( 'id', $parts[0] );
    } 
}

Of course you can also extract the title the same way if you need it.

Don't forget to build your 'article' param when you want to generate urls:

 $this->url( array( 'article' => $id.'_'.$title ) );

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且行且努力 2024-12-12 17:27:44

为了避免处理包含特殊字符的链接，您可以使用 Zend Framework 的此插件。

https://github.com/btlagutoli/CharConvert

$filter2 = new Zag_Filter_CharConvert(array(
               'onlyAlnum' => true,
               'replaceWhiteSpace' => '-'
           ));
echo $filter2->filter('éééé ááááá ? 90 :');//eeee-aaaaa-90

这可以帮助您处理其他语言的字符串

To avoid dealing with the links contain special characters, you can use this plugin for Zend Framework.

https://github.com/btlagutoli/CharConvert

$filter2 = new Zag_Filter_CharConvert(array(
               'onlyAlnum' => true,
               'replaceWhiteSpace' => '-'
           ));
echo $filter2->filter('éééé ááááá ? 90 :');//eeee-aaaaa-90

this can help you deal with strings in other languages

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