文件正被另一个进程使用

发布于 2024-12-05 12:13:17 字数 1002 浏览 0 评论 0原文

private void ButtonCustomarinfoEditClick(object sender, System.Windows.RoutedEventArgs e)
    {
      ByteToImage(fileName,bytesOfImage,fileSize);
    }   

private ImageSource ByteToImage(string fileName, byte[] bytesOfImage, int fileSize)
    {
        FileStream imageFilestream = new FileStream(fileName, FileMode.Create, FileAccess.Write);
        imageFilestream.Write(bytesOfImage, 0, fileSize);
        imageFilestream.Flush();
        imageFilestream.Close();
        imageFilestream.Dispose();
        BitmapImage myBitmapImage = new BitmapImage();
        myBitmapImage.BeginInit();
        myBitmapImage.UriSource = new Uri(fileName);
        myBitmapImage.DecodePixelWidth = 200;
        myBitmapImage.EndInit();
        return myBitmapImage;
    }

当我第一次单击 ButtonCustomarinfoEdit 时，它工作正常。但是当我第二次单击时，它会抛出此异常

捕获：“该进程无法访问文件'C：\ 20.jpg'，因为它正在被另一个进程使用。” （系统.IO.IOException）
异常消息 =“该进程无法访问文件“C:\20.jpg”，因为该文件正在被另一个进程使用。”，异常类型 =“System.IO.IOException”

原文

private void ButtonCustomarinfoEditClick(object sender, System.Windows.RoutedEventArgs e)
    {
      ByteToImage(fileName,bytesOfImage,fileSize);
    }   

private ImageSource ByteToImage(string fileName, byte[] bytesOfImage, int fileSize)
    {
        FileStream imageFilestream = new FileStream(fileName, FileMode.Create, FileAccess.Write);
        imageFilestream.Write(bytesOfImage, 0, fileSize);
        imageFilestream.Flush();
        imageFilestream.Close();
        imageFilestream.Dispose();
        BitmapImage myBitmapImage = new BitmapImage();
        myBitmapImage.BeginInit();
        myBitmapImage.UriSource = new Uri(fileName);
        myBitmapImage.DecodePixelWidth = 200;
        myBitmapImage.EndInit();
        return myBitmapImage;
    }

When i click ButtonCustomarinfoEdit fist time then it work`s fine. But When i click second time then it throw this exception

Caught: "The process cannot access the file 'C:\20.jpg' because it is being used by another process." (System.IO.IOException)
Exception Message = "The process cannot access the file 'C:\20.jpg' because it is being used by another process.", Exception Type = "System.IO.IOException"

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黎夕旧梦 2024-12-12 12:13:17

您的 BitmapImage 对象使文件保持锁定状态。

只是一个小观察，请使用 using 语句像这样：

using(FileStream imageFilestream = new FileStream(fileName, FileMode.Create, FileAccess.Write)) { 
        imageFilestream.Write(bytesOfImage, 0, fileSize); 
}

否则你可能会遇到文件将继续使用的情况（如果在调用 Close() 方法之前发生异常。

Your BitmapImage object keeps the file locked.

Just a small observation, please use the using statement like this:

using(FileStream imageFilestream = new FileStream(fileName, FileMode.Create, FileAccess.Write)) { 
        imageFilestream.Write(bytesOfImage, 0, fileSize); 
}

otherwise you might run into situations that your file will remain in use (if an exception will occur before you call the Close() method.

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