如何从矩阵中分离出一组连续的数字？

发布于 2024-12-05 08:58:16 字数 229 浏览 1 评论 0原文

我有一个 3 列的矩阵。在第二列中，我有一个连续的数字，其增量为 2。假设该列中缺少一个数字，我想形成一个单独的连续数字组，并且我还必须采用相应的值到其他两列。

例如：

在我的情况下，矩阵的阶数非常高，所以，您能告诉我哪个循环适用于这个问题以及如何解决这个问题吗？

原文

I have a matrix with 3 columns. In the second column I have a continuous number which is having a increment of 2. Suppose in that column a number is missing in between, I want to form a separate group of number which is continuous, and also I have to take the values corresponding to the other two columns.

For example:

In my case order of the matrix is very high so, can you please tell me which loop will work for this and how I can solve this?

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忆悲凉 2024-12-12 08:58:16

我不知道我是否 100% 理解你的问题，但我会尝试一下。您可以使用 interp1 函数在丢失的数据点上插入数据。 Interp1 可以通过多种不同的方式进行插值，因此请查看它的帮助文件。对于您给出的矩阵和线性插值，我会执行以下操作：

A = [1 2  3;
 1 4  6;
 1 6  0;
 1 10 3;
 1 12 6];
index = [min(A(:, 2)) : 2 : max(A(:, 2))]';

B = interp1(A(:,2), A(:, [1 3:end]), index, 'linear');

B = [B(:,1) index B(:,2:end)]

B =

    1.00000    2.00000    3.00000
    1.00000    4.00000    6.00000
    1.00000    6.00000    0.00000
    1.00000    8.00000    1.50000
    1.00000   10.00000    3.00000
    1.00000   12.00000    6.00000

希望这有帮助！

I don't know if I understood your question 100% but I'll give this a shot. You can use the interp1 function to interpolate data over your missing datapoint. Interp1 can do interpolation in a variety of different ways so take a look at its help file. In the case of the matrix you gave and with linear interpolation I would do the following:

A = [1 2  3;
 1 4  6;
 1 6  0;
 1 10 3;
 1 12 6];
index = [min(A(:, 2)) : 2 : max(A(:, 2))]';

B = interp1(A(:,2), A(:, [1 3:end]), index, 'linear');

B = [B(:,1) index B(:,2:end)]

B =

    1.00000    2.00000    3.00000
    1.00000    4.00000    6.00000
    1.00000    6.00000    0.00000
    1.00000    8.00000    1.50000
    1.00000   10.00000    3.00000
    1.00000   12.00000    6.00000

Hope this helps!

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