SQL Server：dense_rank（）

Question

我有一个表A： （ID int，batch int，new_batch int）

ID和batch已经填充：

ID  Batch New_Batch
1   01    NULL
2   01    NULL
3   02    NULL
4   02    NULL
5   02    NULL
6   03    NULL
7   04    NULL
8   05    NULL

现在我想根据以下select语句填充New_batch。

(select batch from tableA where id in (3,8))

1. 现在对于这个 select 语句，我们得到batch = 02 和batch =5。现在我想分配new_batch，以便首先对select语句的结果进行排序（batch02然后batch05），其余数据应按批处理的递增顺序而不是在select语句中排序。 （第1、3、4批） 结果应该是：

---

      ID Batch New_Batch
       1   01    03
       2   01    03
       3   02    01
       4   02    01
       5   02    01
       6   03    04
       7   04    05
       8   05    02

谢谢。 PS：可以使用DENSE_RANK()，请不要硬编码！

Answer 1

/*Please provide DDL like the below for future questions*/
DECLARE @tableA TABLE
(
ID INT PRIMARY KEY,
Batch INT,
New_Batch INT NULL
)

INSERT INTO @tableA(ID,Batch)
SELECT 1,1 UNION ALL
SELECT 2,1 UNION ALL   
SELECT 3,2 UNION ALL   
SELECT 4,2 UNION ALL   
SELECT 5,2 UNION ALL   
SELECT 6,3 UNION ALL   
SELECT 7,4 UNION ALL   
SELECT 8,5   

/*Answer*/
;WITH T
     AS (SELECT *,
                DENSE_RANK() OVER (ORDER BY 
                      CASE
                        WHEN Batch IN (SELECT Batch
                                       FROM   @tableA
                                       WHERE  ID IN ( 3, 8 )) 
                         THEN 0 
                         ELSE 1 END, Batch) AS NB
         FROM   @tableA)
UPDATE T
SET    New_Batch = NB

SELECT *
FROM   @tableA  

Answer 2

declare @T table
(
  ID int,
  Batch char(2),
  New_Batch char(2)
)

insert into @T values
(1,   '01',    NULL),
(2,   '01',    NULL),
(3,   '02',    NULL),
(4,   '02',    NULL),
(5,   '02',    NULL),
(6,   '03',    NULL),
(7,   '04',    NULL),
(8,   '05',    NULL)

;with C as
(
  select T1.New_Batch,
         dense_rank() over(order by -T2.ID desc, T1.Batch) as rn
  from @T as T1
    left outer join (select Batch, ID 
                     from @T
                     where ID in (3, 8)) as T2
      on T1.Batch = T2.Batch 
)
update C 
set New_Batch = right(100+rn, 2)


select *
from @T
order by ID

在这里尝试：