通过Python通过蓝牙发送消息或数据

发布于 2024-12-05 07:05:13 字数 608 浏览 0 评论 0 原文

如何通过 python 通过蓝牙发送消息，而不需要像类型数字这样的密钥身份验证？

我用的是pybluez 但我收到此错误：

File "./send", line 12, in <module>
    connect()
File "./send", line 8, in connect
    sock.connect((bd_addr, port))
File "<string>", line 5, in connect
    bluetooth.btcommon.BluetoothError: (111, 'Connection refused')

这是代码

#!/usr/bin/python

import bluetooth

def connect ():
    bd_addr = "x:x:x:x:x:x"
    port = 1
    sock=bluetooth.BluetoothSocket(bluetooth.RFCOMM)
    sock.connect((bd_addr, port))
    sock.send("hello!!")
    sock.close()

connect()

原文

How can i send messages over bluetooth via python without key authentification like type numbers ?

i used pybluez
but i got this error:

File "./send", line 12, in <module>
    connect()
File "./send", line 8, in connect
    sock.connect((bd_addr, port))
File "<string>", line 5, in connect
    bluetooth.btcommon.BluetoothError: (111, 'Connection refused')

Here is the code

#!/usr/bin/python

import bluetooth

def connect ():
    bd_addr = "x:x:x:x:x:x"
    port = 1
    sock=bluetooth.BluetoothSocket(bluetooth.RFCOMM)
    sock.connect((bd_addr, port))
    sock.send("hello!!")
    sock.close()

connect()

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风柔一江水 2024-12-12 07:05:13

正如@TJD所说，您需要确保与所需服务的正确端口绑定。

>>> from bluetooth import *
>>> from pprint import pprint
>>>
>>> devices = discover_devices()
>>> devices
['xx:yy:tt:zz:44:BD', '00:yy:72:zz:bb:aa']

然后，作为第二步，尝试在要连接到的设备上找到服务。

>>> service = find_service(address='00:yy:72:zz:bb:aa')
>>> pprint(service)
[{'description': None,
  'host': '00:yy:72:zz:bb:aa',
  'name': 'Headset Audio Gateway',
  'port': 12,
  'profiles': [('1108', 258)],
  ...},
 {'description': None,
  'host': '00:yy:72:zz:bb:aa',
  'name': 'Dial-Up Networking',
  'port': 1,
  'profiles': [('1103', 256)],
  'protocol': 'RFCOMM',
  ...}]

基于此信息，您可以连接到设备上运行的服务。根据服务/个人资料规格从设备中获取信息。例如，在上面的列表中，您会看到“耳机音频网关”和带有数字'1108'的配置文件列表，这是该服务的简短UID。现在，您可以查找此配置文件的命令，并且应该有效。

As @TJD said, you need to ensure you bind with the correct port for the service you want.

>>> from bluetooth import *
>>> from pprint import pprint
>>>
>>> devices = discover_devices()
>>> devices
['xx:yy:tt:zz:44:BD', '00:yy:72:zz:bb:aa']

Then as the second step try to find the service on the device you want to connect to.

>>> service = find_service(address='00:yy:72:zz:bb:aa')
>>> pprint(service)
[{'description': None,
  'host': '00:yy:72:zz:bb:aa',
  'name': 'Headset Audio Gateway',
  'port': 12,
  'profiles': [('1108', 258)],
  ...},
 {'description': None,
  'host': '00:yy:72:zz:bb:aa',
  'name': 'Dial-Up Networking',
  'port': 1,
  'profiles': [('1103', 256)],
  'protocol': 'RFCOMM',
  ...}]

Based on this information you can connect to a service running on a device. According to the service/profile specification you send service specific commands and get back information from the device. E.g. in the list above you see the 'Headset Audio Gateway' and the profile list with the number '1108', which is the short uuid for the service. You can now lookup the commands for this profile and it should work.

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