SQL Server 2000 查询
我有一个创建的表格,其中包含来自几个用户的多个记录,因此我可以模拟情况。
我创建了以下查询:
SELECT
a.celid, a.callid, a.active, a.messagetext,
b.jactive, a.cel_time, c.username, a.muserid
FROM level2 a, calls b , login c
WHERE a.callid = b.jid
AND a.muserid = c.loginid
AND b.jid = 92
AND a.win = 0
AND b.userid = 12
ORDER BY
cel_time ASC
并结果得到以下查询,
545 92 2 hello1 2 2011-09-18 16:32:17.000 phil01 21
546 92 1 hello2 2 2011-09-18 16:42:38.000 phil01 21
547 92 2 hello3 2 2011-09-18 16:59:08.000 danny 16
548 92 1 hello4 2 2011-09-18 20:46:21.000 phil01 21
549 92 1 hello5 2 2011-09-18 20:47:16.000 phil01 21
550 92 1 hello6 2 2011-09-19 19:32:15.000 phil01 21
551 92 1 hello7 2 2011-09-19 19:34:14.000 phil01 21
但实际上我希望此结果在muserid
上有所不同,并仅返回只返回两个行。
我研究了独特的价值描述,但似乎无法实现这一目标。
我将如何完成?
I have a created a few tables containing multiple records from several users so I can simulate circumstances.
I created the following query:
SELECT
a.celid, a.callid, a.active, a.messagetext,
b.jactive, a.cel_time, c.username, a.muserid
FROM level2 a, calls b , login c
WHERE a.callid = b.jid
AND a.muserid = c.loginid
AND b.jid = 92
AND a.win = 0
AND b.userid = 12
ORDER BY
cel_time ASC
and got the following as result
545 92 2 hello1 2 2011-09-18 16:32:17.000 phil01 21
546 92 1 hello2 2 2011-09-18 16:42:38.000 phil01 21
547 92 2 hello3 2 2011-09-18 16:59:08.000 danny 16
548 92 1 hello4 2 2011-09-18 20:46:21.000 phil01 21
549 92 1 hello5 2 2011-09-18 20:47:16.000 phil01 21
550 92 1 hello6 2 2011-09-19 19:32:15.000 phil01 21
551 92 1 hello7 2 2011-09-19 19:34:14.000 phil01 21
but I actually want this result to be distinct on muserid
and return only return two rows.
I have studied distinct value description but can not seem to get this accomplished.
How would I accomplish this?
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使用此SQL:
Use this SQL: