具有有限缓冲区的生产者/消费者
有人可以检查我的代码并告诉我是否走在正确的轨道上。我似乎有点迷失了。如果您看到我的错误,请让我知道它们。
我想做的是解决有界问题使用我自己的信号量以及 GCD 进行缓冲区。
提前致谢..
sema.c
void procure( Semaphore *semaphore ) {
pthread_mutex_lock(semaphore->mutex1);
while(semaphore->value <= 0)
pthread_cond_wait(&semaphore->condition, semaphore->mutex1);
semaphore->value--;
pthread_mutex_unlock(semaphore->mutex1);
}
void vacate( Semaphore *semaphore ) {
pthread_mutex_lock(semaphore->mutex1);
semaphore->value++;
pthread_cond_signal(&semaphore->condition);
pthread_mutex_unlock(semaphore->mutex1);
}
void init ( Semaphore *semaphore ){
semaphore->value = 1;
pthread_mutex_t myMutex;
semaphore->mutex1 = &myMutex;
pthread_mutex_init( semaphore->mutex1, NULL);
}
void destroy ( Semaphore *semaphore ) {
pthread_mutex_destroy(semaphore->mutex1);
}
和 main.c
struct variables {
Semaphore *sem;
};
struct variables vars;
void constructer (int *buffer, int *in, int *out) {
init(vars.sem);
}
void deconstructer () {
destroy(vars.sem);
}
int rand_num_gen() {
uint_fast16_t buffer;
int file;
int *rand;
file = open("/dev/random", O_RDONLY);
while( 1 ) {
read(file, &buffer, sizeof(buffer));
printf("16 bit number: %hu\n", buffer );
*rand = (int) buffer;
close(file);
break;
}
return *rand;
}
void put_buffer( int* buffer, int* in, int* out ) {
buffer[*in] = rand_num_gen(); // produce
procure(vars.sem); // wait here
*in = (*in + 1) % BUF_SIZE;
vacate(vars.sem);
}
void get_buffer( int* buffer, int* in, int* out ) {
int value;
procure(vars.sem);
value = buffer[*out];
vacate(vars.sem);
*out = (*out + 1) % BUF_SIZE;
}
int main (void) {
int *in, *out, *buffer;
constructer(buffer, in, out);
dispatch_queue_t producer, consumer;
producer = dispatch_queue_create("put_buffer", NULL);
consumer = dispatch_queue_create("get_buffer", NULL);
dispatch_async(producer,
^{
int i;
do
{
put_buffer( buffer, in, out );
dispatch_async(consumer,
^{
get_buffer( buffer, in, out );
if (i == RUN_LENGTH) exit(EXIT_SUCCESS);
});
}
while (i < RUN_LENGTH);
});
dispatch_main();
deconstructer();
exit (0);
}
Could someone check my code and tell me if I am on the right track.. It seems like I am a bit lost.. if you see my errors, please let me know them..
What I am trying to do is to solve bounded buffer using my own semaphores as well as GCD.
Thanks in advance..
sema.c
void procure( Semaphore *semaphore ) {
pthread_mutex_lock(semaphore->mutex1);
while(semaphore->value <= 0)
pthread_cond_wait(&semaphore->condition, semaphore->mutex1);
semaphore->value--;
pthread_mutex_unlock(semaphore->mutex1);
}
void vacate( Semaphore *semaphore ) {
pthread_mutex_lock(semaphore->mutex1);
semaphore->value++;
pthread_cond_signal(&semaphore->condition);
pthread_mutex_unlock(semaphore->mutex1);
}
void init ( Semaphore *semaphore ){
semaphore->value = 1;
pthread_mutex_t myMutex;
semaphore->mutex1 = &myMutex;
pthread_mutex_init( semaphore->mutex1, NULL);
}
void destroy ( Semaphore *semaphore ) {
pthread_mutex_destroy(semaphore->mutex1);
}
and main.c
struct variables {
Semaphore *sem;
};
struct variables vars;
void constructer (int *buffer, int *in, int *out) {
init(vars.sem);
}
void deconstructer () {
destroy(vars.sem);
}
int rand_num_gen() {
uint_fast16_t buffer;
int file;
int *rand;
file = open("/dev/random", O_RDONLY);
while( 1 ) {
read(file, &buffer, sizeof(buffer));
printf("16 bit number: %hu\n", buffer );
*rand = (int) buffer;
close(file);
break;
}
return *rand;
}
void put_buffer( int* buffer, int* in, int* out ) {
buffer[*in] = rand_num_gen(); // produce
procure(vars.sem); // wait here
*in = (*in + 1) % BUF_SIZE;
vacate(vars.sem);
}
void get_buffer( int* buffer, int* in, int* out ) {
int value;
procure(vars.sem);
value = buffer[*out];
vacate(vars.sem);
*out = (*out + 1) % BUF_SIZE;
}
int main (void) {
int *in, *out, *buffer;
constructer(buffer, in, out);
dispatch_queue_t producer, consumer;
producer = dispatch_queue_create("put_buffer", NULL);
consumer = dispatch_queue_create("get_buffer", NULL);
dispatch_async(producer,
^{
int i;
do
{
put_buffer( buffer, in, out );
dispatch_async(consumer,
^{
get_buffer( buffer, in, out );
if (i == RUN_LENGTH) exit(EXIT_SUCCESS);
});
}
while (i < RUN_LENGTH);
});
dispatch_main();
deconstructer();
exit (0);
}
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你的代码有一个错误。在
init
函数中,您将局部变量的地址分配给semaphore->mutex1
,当函数返回时,该地址将无效。稍后您仍然使用该地址,因此这会导致未定义的行为。您必须直接在信号量中(不使用指针)为互斥体分配内存,或者通过 malloc 分配内存。
更新:
您的程序有如此多的错误,您绝对应该选择一个更简单的主题来学习有关内存管理的基本概念,如何分配、使用和引用缓冲区,进行正确的错误处理等。在这里是您的代码的稍微编辑过的版本。它仍然行不通,但可能有一些你应该遵循的想法。
正如我所说,我没有发现所有错误。
Your code has a bug. In the
init
function you assign the address of a local variable tosemaphore->mutex1
, and when the function returns this address will be invalid. Later you still use this address, so this leads to undefined behavior.You must either allocate the memory for the mutex directly in the semaphore (without a pointer) or allocate the memory via
malloc
.Update:
Your program has so many bugs that you should definitely pick an easier topic to learn the basic concepts about memory management, how to allocate, use and reference a buffer, do proper error handling, etc. Here is a slightly edited version of your code. It still won't work, but probably has some ideas that you should follow.
As I said, I didn't catch all the bugs.