JavaScript：用“or”声明 VAR陈述

发布于 2024-12-05 04:11:33 字数 376 浏览 0 评论 0原文

类似

var $page_products = $page_name == 'products-uninterruptible-power-supply.php' OR 'products-uninterruptible-power-supply-np2031.php';

该代码与我已经尝试使用的

var $page_products = $page_name == 'products-uninterruptible-power-supply.php' || 'products-uninterruptible-power-supply-np2031.php';

，但它仍然无法正常工作。提前致谢！

原文

the code is something like this

var $page_products = $page_name == 'products-uninterruptible-power-supply.php' OR 'products-uninterruptible-power-supply-np2031.php';

i already tried using

var $page_products = $page_name == 'products-uninterruptible-power-supply.php' || 'products-uninterruptible-power-supply-np2031.php';

but it is still not working. thanks in advance!

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清晰传感 2024-12-12 04:11:33

假设您的目的是声明一个变量 $page_products，如果 $page_name 等于这两个字符串之一，则该变量将设置为 true，否则设置为 false，请执行以下操作：

var $page_products = $page_name == 'products-uninterruptible-power-supply.php'
           || $page_name == 'products-uninterruptible-power-supply-np2031.php';

编辑：我刚刚注意到两个页面名称都以相同的四个单词开头，因此您不必与每个字符串进行比较，而是可以测试 $page_name 中的值是否以这些单词开头，例如， :

var $page_products =
           $page_name.indexOf('products-uninterruptible-power-supply') === 0;

Assuming your intention is to declare one variable, $page_products, which will be set to true if the $page_name is equal to either of those two strings and false otherwise, do this:

var $page_products = $page_name == 'products-uninterruptible-power-supply.php'
           || $page_name == 'products-uninterruptible-power-supply-np2031.php';

EDIT: I just noticed that both page names start with the same four words, so instead of comparing to each string it may suit you to test whether the value in $page_name starts with those words, e.g.,:

var $page_products =
           $page_name.indexOf('products-uninterruptible-power-supply') === 0;

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寻找我们的幸福 2024-12-12 04:11:33

这应该有效

var $page_products = ($page_name == 'products-uninterruptible-power-supply.php' || $page_name == 'products-uninterruptible-power-supply-np2031.php');

This should work

var $page_products = ($page_name == 'products-uninterruptible-power-supply.php' || $page_name == 'products-uninterruptible-power-supply-np2031.php');

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许你一世情深 2024-12-12 04:11:33

如果您想有条件地分配文件名，那么您将需要三元运算符：

var $page_products = ($page_name == 'products-uninterruptible-power-supply.php') ?
    'products-uninterruptible-power-supply.php' : 
    'products-uninterruptible-power-supply-np2031.php';

If you want to assign the file name conditionally, then you'll want the ternary operator:

var $page_products = ($page_name == 'products-uninterruptible-power-supply.php') ?
    'products-uninterruptible-power-supply.php' : 
    'products-uninterruptible-power-supply-np2031.php';

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