将 JSON 数据放入 NSURL 中

发布于 2024-12-05 00:38:00 字数 668 浏览 0 评论 0原文

我正在尝试做一些看似理所当然的事情，但由于某种原因不起作用。

我正在尝试发出 JSON 数据的获取请求，并在 URL 中发送 JSON“数据”参数。

这是我正在使用的代码：

NSDictionary *whatToPost= [NSDictionary dictionaryWithObjectsAndKeys:
 username, @"username", 
 password, @"password", nil];

NSString *url = [NSString stringWithFormat:@"http://domain.com/user/get?data=%@",
 [whatToPost JSONString]];
NSURL *theUrl = [NSURL URLWithString:
 [url stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
//NSLog(url) will produce this:
  http://domain.com/user/get?data={"username":"test1","password":"poop"}

当我设置断点时，theUrl 为空。我不太明白为什么它会被破坏，但我认为发送 { 或 " 会破坏它。有什么想法吗？我应该切换到 POST 吗？

原文

I'm trying to do something that seems like a no brainer, but for some reason isn't working.

I'm trying to make a get request for JSON data, sending a JSON 'data' parameter in the URL.

Here's the code I'm using:

NSDictionary *whatToPost= [NSDictionary dictionaryWithObjectsAndKeys:
 username, @"username", 
 password, @"password", nil];

NSString *url = [NSString stringWithFormat:@"http://domain.com/user/get?data=%@",
 [whatToPost JSONString]];
NSURL *theUrl = [NSURL URLWithString:
 [url stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
//NSLog(url) will produce this:
  http://domain.com/user/get?data={"username":"test1","password":"poop"}

When I set a breakpoint, theUrl is null. I can't quite figure out why it's breaking, but I figure something about sending the {'s or "'s is breaking it. Any ideas? Should I just switch to POST?

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飘过的浮云 2024-12-12 00:38:00

NSDictionary *whatToPost= [NSDictionary dictionaryWithObjectsAndKeys:
 username, @"username", 
 password, @"password", nil];

NSString *url = [NSString stringWithFormat:@"http://domain.com/user/get?data=%@",
 [whatToPost JSONString]];
NSURL *theUrl = [NSURL URLWithString:
 [url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];

您切换了方法

stringByAddingPercentEscapesUsingEncoding：

使用给定编码返回接收者的表示形式，以确定将接收者转换为合法 URL 字符串所需的转义百分比。

通过stringByReplacingPercentEscapesUsingEncoding

返回一个新字符串，该字符串是通过在接收器中用给定编码确定的匹配字符替换所有百分比转义符而生成的。

请参阅：
http://developer.apple.com/library /mac/#documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/Reference/NSString.html
http://blog.evandavey.com/2009/ 01/如何对 url-encode-nsstring-in-objective-c.html

NSDictionary *whatToPost= [NSDictionary dictionaryWithObjectsAndKeys:
 username, @"username", 
 password, @"password", nil];

NSString *url = [NSString stringWithFormat:@"http://domain.com/user/get?data=%@",
 [whatToPost JSONString]];
NSURL *theUrl = [NSURL URLWithString:
 [url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];

you switched method

stringByAddingPercentEscapesUsingEncoding:

Returns a representation of the receiver using a given encoding to determine the percent escapes necessary to convert the receiver into a legal URL string.

by stringByReplacingPercentEscapesUsingEncoding