删除除 '<' 之间的字符之外的所有内容& '>，'在 Vim 中 -- 从 Gmail“收件人”中提取电子邮件地址场地

发布于 2024-12-05 00:26:17 字数 1575 浏览 1 评论 0 原文

我有一个以逗号分隔的电子邮件地址列表，每个实际地址前面都带有联系人姓名（来自 Gmail）。下面是一个示例：

Fred Flintstone <[email protected]>, Wilma Flintstone <[email protected]>, Barney Rubble <[email protected]>, Bamm-Bamm Rubble <[email protected]>,

转换为：

[email protected], [email protected], [email protected], [email protected],

背景信息：我正在尝试将联系人列表粘贴到 webex 邀请中，该邀请仅接受电子邮件地址。

删除 Vim 中除正则表达式匹配之外的所有内容相关，但所有电子邮件在这种情况下，地址在一行上。

原文

I have a comma-delimited list of email addresses with each actual address prepended by the contact's name (from Gmail). Here's an example:

Fred Flintstone <[email protected]>, Wilma Flintstone <[email protected]>, Barney Rubble <[email protected]>, Bamm-Bamm Rubble <[email protected]>,

converts to:

[email protected], [email protected], [email protected], [email protected],

Background info: I am trying to paste the list of contacts into a webex invite, which can only accept email addresses.

Remove everything except regex match in Vim is related, but all the email addresses are on one line in this case.

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预谋 2024-12-12 00:26:17

你尝试过吗？

:s/.\{-}\%(\(,\s*\)\|<\(.\{-}\)>\)/\1\2/g

以下也将起作用：

:s/.*/\=join(map(split(submatch(0), ','), "matchstr(v:val, '<\\zs.*\\ze>')"), ', ')

Have you tried?

:s/.\{-}\%(\(,\s*\)\|<\(.\{-}\)>\)/\1\2/g

The following will also work:

:s/.*/\=join(map(split(submatch(0), ','), "matchstr(v:val, '<\\zs.*\\ze>')"), ', ')

回复收藏 0 原文

笑叹一世浮沉 2024-12-12 00:26:17

使用 awk

    echo "Fred Flintstone <[email protected]>, Wilma Flintstone <[email protected]>, Barney Rubble <[email protected]>, Bamm-Bamm Rubble <[email protected]>
"|awk -F'<|>' '{for (i=1;i<=NF;i++)printf (i%2==0)?$i",":""}'

或在 VIM 中

:%s/,/\r/g
:%s/.*<\(.*\)>/\1/g

with awk

    echo "Fred Flintstone <[email protected]>, Wilma Flintstone <[email protected]>, Barney Rubble <[email protected]>, Bamm-Bamm Rubble <[email protected]>
"|awk -F'<|>' '{for (i=1;i<=NF;i++)printf (i%2==0)?$i",":""}'

or in VIM