如何“减少输入以创建 C”类型”使用统一初始化器？

发布于 2024-12-05 00:21:14 字数 604 浏览 1 评论 0原文

我用 {} 玩过很多新的统一初始化。像这样：

vector<int> x = {1,2,3,4};
map<int,string> getMap() {
    return { {1,"hello"}, {2,"you"} };
}

毫无争议的是，这个初始化可能会改变我们的C++编程。但我想知道在阅读 Herb Sutter 常见问题解答。

Alfonse：统一初始化（在可以推导出正在构造的类型时使用 {} 调用构造函数）有可能从根本上减少创建 C++ 类型所需的键入量。它就像 lambda 一样，将改变人们编写 C++ 代码的方式。 [...]

有人能给我举个例子来说明 Alfonse 在这里的具体设想吗？

原文

I have played a lot the new Uniform Initialization with {}. Like this:

vector<int> x = {1,2,3,4};
map<int,string> getMap() {
    return { {1,"hello"}, {2,"you"} };
}

It is undisputed that this initialization may change we program C++.
But I wonder if I missed some of the magic possibilities when reading Alfonses's question in the Herb Sutter FAQs.

Alfonse: Uniform initialization (the use of {} to call constructors when the type being constructed can be deduced) has the potential to radically reduce the quantity of typing necessary to create C++ types. It's the kind of thing, like lambdas, that will change how people write C++ code. [...]

Can someone give me an example of what Alfonse exactly envisions here?

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奈何桥上唱咆哮 2024-12-12 00:21:14

我认为他的意思

std::vector<int> x{1, 2, 3, 4};
std::map<int, std::string> y{{1, "hello"}, {2, "you"}};

是这比

std::vector<int> x;
x.push_back(1);
x.push_back(2);
x.push_back(3);
x.push_back(4);
std::map<int, std::string> y;
y.emplace(1, "hello");
y.emplace(2, "you");

I assume he means that

std::vector<int> x{1, 2, 3, 4};
std::map<int, std::string> y{{1, "hello"}, {2, "you"}};

is significantly less typing than

std::vector<int> x;
x.push_back(1);
x.push_back(2);
x.push_back(3);
x.push_back(4);
std::map<int, std::string> y;
y.emplace(1, "hello");
y.emplace(2, "you");

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