正则表达式过滤具有特定属性的 XAML 标签

发布于 2024-12-04 22:55:43 字数 275 浏览 1 评论 0原文

我有以下与 XAML 标签匹配的正则表达式：

<[^<>]*>

这将返回这两行：

<Button x:Name="Button1" />
<Button x:Name="Button2" Content="foo" />

我想要做的是过滤掉其中包含“Content =“foo””的标签。

那里有类似的例子，但在这种情况下，引号让我绊倒。

有什么想法吗？

原文

I have the following Regex that matches XAML tags:

<[^<>]*>

This would return both of these lines:

<Button x:Name="Button1" />
<Button x:Name="Button2" Content="foo" />

What I want to do is filter out tags that have "Content="foo"" in them.

There are similar examples out there, but in this case the quotation marks are tripping me up.

Any ideas?

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影子是时光的心 2024-12-11 22:55:43

正则表达式

/<[^>]*Content="foo".*?>/g

这意味着启动正则表达式 (/) 并搜索 < 后跟零个或多个而不 > ([^>]*) 后跟 Content="foo" 后跟零个或多个任何内容 (.*) un -贪婪地，后跟“>”并结束正则表达式 /。

测试代码：

用javascipt编写，但可以轻松移植到其他语言。

x = ['<Button x:Name="Button1" /><Button x:Name="Button2" Content="foo" /><Button x:Name="Button1" /><Button Content="foo" />']

console.log( x[0].match(/<[^>]*Content="foo".*?>/g) )

更新为匹配完全相反的（根据OP的要求）

正则表达式

使用否定先行断言，如详细信息此处

<((?!Content="foo")[^>])*>

这意味着匹配 < 后跟零个或多个非 > ([^>]*) 每个前面都没有 Content="foo" ，后跟 >。添加括号用于必要的分组。

但请记住 - 使用正则表达式代替 XML 解析会让堆栈溢出的人对你非常生气......所以最好匿名发布这样的问题。 ;)

Regex

/<[^>]*Content="foo".*?>/g

Which means start regex (/) and search for < folled by zero or more not >s ([^>]*) followed by Content="foo" followed by zero or more anythings (.*) un-greedily, followed by '>' and end regex /.

Test Code:

Written in javascipt, but can be ported into other languages easily.

x = ['<Button x:Name="Button1" /><Button x:Name="Button2" Content="foo" /><Button x:Name="Button1" /><Button Content="foo" />']

console.log( x[0].match(/<[^>]*Content="foo".*?>/g) )

Updated to match exact opposite (as required by OP)

Regex

Using negative lookahead assertion, as detailed here

<((?!Content="foo")[^>])*>

Which means match < followed by zero or more not >s ([^>]*) that each do not have Content="foo" in front of them followed by >. Brackets added for necessary grouping.

But remember - using regex as a substitute for XML parsing will make people on stack overflow get really angry with you... so better to post questions like this anonymously. ;)

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傾旎 2024-12-11 22:55:43

<([^<>](?!\sContent\s*=\s*("foo"|'foo')))*>

这...但是请不要使用正则表达式来解析 XML。

我们使用 [^<>] 捕获的每个字符都会检查它后面是否有一个空格和 Content="foo"。如果为 true，我们会失败，因此捕获会回滚一个字符，并且正则表达式会检查终止 >。

http://regexr.com?2umr9

您必须单击一下，以便“激活”正则表达式。

一些小注意事项：这个正则表达式是错误的，因为它试图解析 XML，但是忽略这一点，它不会被 SContent="foo" （忽略）或 Content='foo' 愚弄（捕获）或 :Content='foo'（忽略）或 Content = "foo"（捕获）。如果您使用将 \s 视为与 XML 相同的空格字符列表的正则表达式解析器，这一点就很明显了:-) 否则，一些“奇怪的、外来的”空格可能会稍微破坏它。请记住将其与区分大小写的解析一起使用！

<([^<>](?!\sContent\s*=\s*("foo"|'foo')))*>

This... But PLEASE, don't use Regexes to parse XML.

Each character we capture with [^<>] we check if it is followed by one space and the Content="foo". If true we fail so the capture is rollbacked of one character and the Regex checks for the terminating >.

http://regexr.com?2umr9

You have to click around a little so that the Regex is "activated".

Some small notes: this Regex is WRONG because it's trying to parse XML, but ignoring this, it won't be fooled by SContent="foo" (ignored) or Content='foo' (catched) or :Content='foo' (ignored) or Content = "foo" (catched). This clearly if you are using a Regex parser that treats \s as the same list of space characters as XML :-) Otherwise some "strange, alien" spaces could break it a little. Remember to use it with case sensitive parsing!

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