在matlab中绕y轴旋转3D点

发布于 2024-12-04 22:16:32 字数 362 浏览 0 评论 0原文

我已经获得了一个可以使用的旋转矩阵：

matrix

并已将矩阵输入到我的函数中，

theta = radians(theta);
Ry(theta) = [cos(theta) 0 sin(theta); 0 1 0; -sin(theta) 0 cos(theta)];
newpose = pos*Ry(theta);

只要函数达到这个阶段它返回错误

???下标索引必须是实数正整数或逻辑。

非常感谢任何帮助

原文

I have been provided with a rotation matrix to use:

matrix

and have entered the matrix into my function as

theta = radians(theta);
Ry(theta) = [cos(theta) 0 sin(theta); 0 1 0; -sin(theta) 0 cos(theta)];
newpose = pos*Ry(theta);

yet whenever the function reaches this stage it returns the error

??? Subscript indices must either be real positive integers or
logicals.

any help much appreciated

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梦与时光遇 2024-12-11 22:16:32

问题在于Ry(theta)。如果您希望它是一个变量，请将其命名为Ry_theta，或者将其放入实际的函数中。这应该有效：

theta = radians(theta);
Ry_theta = [cos(theta) 0 sin(theta); 0 1 0; -sin(theta) 0 cos(theta)];
newpose = pos*Ry_theta;

或者 - 如果您想要一个更可重用的解决方案：

% in your existing file:
theta = radians(theta);
newpose = pos*rotationAboutYAxis(theta);;

% in a file called rotationAboutYAxis.m:
function Ry = rotationAboutYAxis(theta)
Ry = [cos(theta) 0 sin(theta); 0 1 0; -sin(theta) 0 cos(theta)];

The problem is the Ry(theta). Call it something like Ry_theta if you want it to be a variable, or put it in an actual function. This should work:

theta = radians(theta);
Ry_theta = [cos(theta) 0 sin(theta); 0 1 0; -sin(theta) 0 cos(theta)];
newpose = pos*Ry_theta;

Or - if you want a more reusable solution:

% in your existing file:
theta = radians(theta);
newpose = pos*rotationAboutYAxis(theta);;

% in a file called rotationAboutYAxis.m:
function Ry = rotationAboutYAxis(theta)
Ry = [cos(theta) 0 sin(theta); 0 1 0; -sin(theta) 0 cos(theta)];

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