持有人模式接近差异和性能比较
我见过两种方法做同样的事情，我不知道什么更快，什么更好，以及有什么区别。 。 。
我的意思是只有这几行是不同的，其他一切都是一样的，但仍然有两种方法，我不明白有什么不同，哪种方法更快
案例一：
public View getView(int position, View convertView,ViewGroup parent) {
View row=super.getView(position, convertView, parent);
ViewHolder holder=(ViewHolder)row.getTag();
情况二：
public View getView(int position, View convertView,ViewGroup parent) {
//of course some checks if the convertView is null, but that is not the point
ViewHolder holder=(ViewHolder)convertView.getTag();
还有一个子问题：- ） 我如何测试哪个更快？我的意思是我应该如何测试适配器的性能？
谢谢
I have seen two ways of doing the same thing, and I do not know what is faster and what is better , and what is the difference . . .
I mean only this few row at the begging are differences and everything else is the same, but still there are two approaches and I do not understand what is different and which way is faster
case one:
public View getView(int position, View convertView,ViewGroup parent) {
View row=super.getView(position, convertView, parent);
ViewHolder holder=(ViewHolder)row.getTag();
case two:
public View getView(int position, View convertView,ViewGroup parent) {
//of course some checks if the convertView is null, but that is not the point
ViewHolder holder=(ViewHolder)convertView.getTag();
one more sub-question :-)
How can I test what is faster ? I mean how should I do testing for performance on adapters ?
Thanks
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不同的是，第一个方法链接到超类，而第二个方法则不是。
使用 Traceview。
What is different is that the first one is chaining to the superclass, and the second one is not.
Use Traceview.