sinatra put 方法不起作用
您好，提交表单时，“put”方法用于将数据从表单发送到 sinatra。put 方法在 app.rb 中定义，put 方法调用显示两个值的 erb 文件。
但没有显示任何内容，有人可以帮忙吗？
put '/form' do
@name = params[:FirstName]
@last = params[:LastName]
erb :formact
end
表格
<form name="biodata" action="form" method="put" onsubmit="validateForm()">
code
</form>
谢谢
Hi on submission of the form 'put' method is used to send data from form to sinatra.the put method is defined in app.rb put method makes a call to erb file which displays the two values.
but nothing is being displayed could somebody help please.
put '/form' do
@name = params[:FirstName]
@last = params[:LastName]
erb :formact
end
form
<form name="biodata" action="form" method="put" onsubmit="validateForm()">
code
</form>
Thank you
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您无法直接从浏览器发送
PUT请求，但您可以使用 Sinatra 的method_override选项，在经典风格中默认设置为 true。如果您使用模块化样式，则必须使用enable :method_override启用它。这会检查传入的请求是否包含名为
_method的参数，如果找到，则调用的请求方法将更改为该参数的值，以便应用程序的其余部分认为该调用是使用该参数进行的HTTP 方法。让
put方法正常工作的方法是在表单中使用POST方法，但要包含名称为“_method”、值“put”的隐藏输入。与 Rails 中使用的技术相同（事实上，它与使用的中间件相同 -
Rack::MethodOverride）。You can't send a
PUTrequest directly from a browser, but you can fake it using Sinatra'smethod_overrideoption, which is set to true by default in classic style. If you’re using modular style you’ll have to enable it withenable :method_override.This checks incoming requests for a parameter named
_method, and if it finds one the request method of the call is changed to the parameter's value so it appears to the rest of the app that the call was made using that HTTP method.The way to get your
putmethod to work is to use thePOSTmethod in your form, but to include a hidden input with name "_method" and value "put"This is the same technique that is used in Rails (in fact it's the same middleware that's used -
Rack::MethodOverride).我不认为
PUT是表单提交的有效方法。检查您的 HTTP 服务器日志，看看请求是否实际上以PUT请求的形式发出——浏览器可能会以GET的形式发送它们，这是默认情况。无论如何，您应该只使用
POST来代替。I don't think
PUTis a valid method for form submission. Check your HTTP server log and see if the requests are actually coming asPUTrequests -- the browser might be sending them asGET, which is the default.Anyway, you should probably just use
POSTinstead.