如何在目标c中动态创建无符号字符类型数组
我想根据另一个 nsmutablearray 的值在 Objective c 中创建一个 unsigned char 数组, 请帮助我,
unsigned char buffer2[24];
buffer2[0] = 0X55; buffer2[1]=0x66; buffer2[2]=0x77; buffer2[3]=0x88; buffer2[4]=0x44;//print command
buffer2[5] = 0X1D; buffer2[6]=0x6B; buffer2[7]=02; buffer2[8]=0x0D;
buffer2[9] = 0X35; buffer2[10]=0x30; buffer2[11]=0x30; buffer2[12]=0x30; buffer2[13]=0x33;
buffer2[14] = 0X35; buffer2[15]=0x37; buffer2[16]=0x37; buffer2[17]=0x30; buffer2[18]=0x33;
buffer2[19] = 0X30; buffer2[20]=0x31; buffer2[21]=0x38; buffer2[22]=0x37; buffer2[23]=0x30;
我想动态传递该数组的值。
提前致谢。 希瓦姆
I want to create an unsigned char array in objective c from the values of another nsmutablearray,
Please help me
unsigned char buffer2[24];
buffer2[0] = 0X55; buffer2[1]=0x66; buffer2[2]=0x77; buffer2[3]=0x88; buffer2[4]=0x44;//print command
buffer2[5] = 0X1D; buffer2[6]=0x6B; buffer2[7]=02; buffer2[8]=0x0D;
buffer2[9] = 0X35; buffer2[10]=0x30; buffer2[11]=0x30; buffer2[12]=0x30; buffer2[13]=0x33;
buffer2[14] = 0X35; buffer2[15]=0x37; buffer2[16]=0x37; buffer2[17]=0x30; buffer2[18]=0x33;
buffer2[19] = 0X30; buffer2[20]=0x31; buffer2[21]=0x38; buffer2[22]=0x37; buffer2[23]=0x30;
I want to pass values of this array dynamically.
Thanks in advance.
Shivam
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您可以使用 C 的
malloc
或calloc
函数:使用后不要忘记释放它:
简单的例子:
You can use
malloc
orcalloc
functions of C:Don't forget to free it after using:
Simple example: