在没有 Math 类库的情况下用 C# 进行除法

发布于 2024-12-04 15:51:21 字数 634 浏览 3 评论 0原文

我编写了一个不带任何算术字符进行除法的程序，代码如下：

        int num1;
        int num2;

        Console.WriteLine("Enter first number");
        int.TryParse(Console.ReadLine(), out num1);

        Console.WriteLine("Enter Second Number");
        int.TryParse(Console.ReadLine(), out num2);
        int sum = 0;

        sum = num1;
        int counter = 0;

        while (sum > 0)
        {
            sum -= num2;
            counter += 1;
        }
        Console.WriteLine("The division of the two numbers is " + counter);

我现在想让它显示除法的余数，例如 10 / 3 将显示 1，因为总和还剩下 1。

我该怎么做呢？我应该使用什么样的循环以及它与我的除法循环有多相似？

原文

I have made a program that divides without any arithmetic characters, here is the code:

        int num1;
        int num2;

        Console.WriteLine("Enter first number");
        int.TryParse(Console.ReadLine(), out num1);

        Console.WriteLine("Enter Second Number");
        int.TryParse(Console.ReadLine(), out num2);
        int sum = 0;

        sum = num1;
        int counter = 0;

        while (sum > 0)
        {
            sum -= num2;
            counter += 1;
        }
        Console.WriteLine("The division of the two numbers is " + counter);

I would now like to make it show the remainder of a division e.g. 10 / 3 will show 1 as there is 1 left from the sum.

How would I go about doing it? What kind of loop should I use and how similar is it to my division loop?

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毁梦 2024-12-11 15:51:21

var rem = num1;
while (rem >= num2)
{
  rem -= num2;
}

Console.WriteLine("The remainder is " + rem);

或者如果你想让它变得非常简单，那么在循环之后：

var rem = sum + num2;

由于你的程序有缺陷，你应该将循环更改为：

while (sum >= num2)
{
  sum -= num2;
  counter += 1;
}

然后你在 counter 中得到除法结果，在 sum< 中得到余数/代码>。

var rem = num1;
while (rem >= num2)
{
  rem -= num2;
}

Console.WriteLine("The remainder is " + rem);

or if you want to make it really easy then after your loop:

var rem = sum + num2;

Since your program is flawed you should change the loop to:

while (sum >= num2)
{
  sum -= num2;
  counter += 1;
}

Then you have the division result in counter and the remainder in sum.

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七色彩虹 2024-12-11 15:51:21

然后将此行更改

while (sum > 0)

为

while (sum >= num2 )

sum将保留其余部分，Counter实际上将给出正确的结果。

Change this line

while (sum > 0)

to this

while (sum >= num2 )

then sum will hold the remainder, and counter will actually give the correct result.

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白日梦 2024-12-11 15:51:21

余数将为sum + num2。

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游魂 2024-12-11 15:51:21

更改 while

while (sum >= num2)

并在末尾添加

Console.WriteLine("The remainder of the division of the two numbers is " + sum);

Change the while in

while (sum >= num2)

and add at the end

Console.WriteLine("The remainder of the division of the two numbers is " + sum);

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寒江雪… 2024-12-11 15:51:21

我确实希望这只是一个练习，看看你是否可以在不实际除法的情况下进行除法，而不是真正尝试制定有效的除法算法！

我不想看到计算1,000,000,000 / 1需要多长时间

无论如何，如果你必须这样做，那么余数将是sum加上的最终值num2。

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誰ツ都不明白 2024-12-11 15:51:21

while (sum >= num2 ) // <- changed
{
    sum -= num2;
    counter += 1;
}
Console.WriteLine("The division of the two numbers is " + counter);
Console.WriteLine("The remainder of the two numbers is " + sum);

while (sum >= num2 ) // <- changed
{
    sum -= num2;
    counter += 1;
}
Console.WriteLine("The division of the two numbers is " + counter);
Console.WriteLine("The remainder of the two numbers is " + sum);

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