是否可以获取HttpExchange的原始请求？
如何从 com.sun.net.httpserver.HttpExchange 获取原始请求？
我正在使用 HttpServer 来制作代理，因此我想获取原始 http 请求并将其发送到原始主机。
How can I get the raw request from com.sun.net.httpserver.HttpExchange?
I'm using HttpServer to make a proxy, so I want to get the raw http request and send it to the original host.
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HttpExchangeAPI 不支持此功能。您（当然）可以自由地创建自己的类来扩展 HttpExchange 并根据需要实现其方法。 （该类实际上只是一组抽象方法。）唯一的其他可能性是查看 Sun/Oracle 代码库中
HttpExchange的某些现有实现。我对如何有效实现
HttpExchange的直觉是，通用实现不会捕获原始请求消息。即使确实如此，您也必须“探索”代码不应直接使用的类的内部结构。出于显而易见的原因，这是一个坏主意。
The
HttpExchangeAPI does not support this. You are (of course) free to create your own class that extendsHttpExchangeand implements its methods however you want. (The class is really just a set of abstract methods.)The only other possibility would be to look at some existing implementation of
HttpExchangein the Sun/Oracle codebase.My intuition of how
HttpExchangewould be implemented efficiently is that a generic implementation wouldn't capture the raw request message.Even if it did, you would have to "poke around" with the internals of a class that your code shouldn't be using directly. This is a bad idea for obvious reasons.