使用 php 获取 intval() ？

发布于 2024-12-04 13:01:25 字数 181 浏览 1 评论 0原文

假设我有以下字符串：

danger13 afno 1 900004

使用 intval() 它给了我 13，但是，我想获取字符串中的最大整数，即 9000004，我怎样才能实现这一点？

编辑：字符串有不同的形式，我不知道最大的数字在哪里。

原文

let's say I have the following string:

danger13 afno 1 900004

using intval() it gives me 13, however, I want to grab the highest integer in the string, which is 9000004, how can I achieve this?

Edit: the string comes in different forms, and I don't know where the highest number will be.

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久伴你 2024-12-11 13:01:25

您需要从字符串中取出所有整数，然后找到最大的...

$str = "danger13 afno 1 900004";
preg_match_all('/\d+/', $str, $matches); // get all the number-only patterns
$numbers = $matches[0];

$numbers = array_map('intval', $numbers); // convert them to integers from string

$max = max($numbers); // get the largest

$max 现在是 900004。

请注意，这非常简单。如果您的字符串中有任何与模式 \d+ （1 个或多个数字）匹配的内容，但您不想将其作为单独的整数进行匹配（例如 43.535 将返回 535)，这不会让您满意。您需要更仔细地定义您的意思。

You'll need to get all the integers out of the string, then find the biggest...

$str = "danger13 afno 1 900004";
preg_match_all('/\d+/', $str, $matches); // get all the number-only patterns
$numbers = $matches[0];

$numbers = array_map('intval', $numbers); // convert them to integers from string

$max = max($numbers); // get the largest

$max is now 900004.

Note that this is very simple. If your string has anything that matches the pattern \d+ (1 or more digits) that you don't want to match as a separate integer (e.g. 43.535 would return 535), this won't be satisfactory for you. You'll need to define more closely what you mean.

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演多会厌 2024-12-11 13:01:25

对于字符串中按字典顺序排列的最高整数值（最多 PHP_INT_MAX），您可以将数字分开并获取最大值：

$max = max(preg_split('/[^\d]+/', $str, NULL, PREG_SPLIT_NO_EMPTY));

演示。

或者更好的自我记录：

$digitsList = preg_split('/[^\d]+/', $str, NULL, PREG_SPLIT_NO_EMPTY);
if (!$digitsList)
{
    throw new RuntimeException(sprintf('Unexpected state; string "%s" has no digits.', $str));
}
$max = max($digitsList);

For the lexicographical highest integer value within the string (up to PHP_INT_MAX) you can just split the numbers apart and get the maximum value:

$max = max(preg_split('/[^\d]+/', $str, NULL, PREG_SPLIT_NO_EMPTY));

Demo.

Or better self-documenting:

$digitsList = preg_split('/[^\d]+/', $str, NULL, PREG_SPLIT_NO_EMPTY);
if (!$digitsList)
{
    throw new RuntimeException(sprintf('Unexpected state; string "%s" has no digits.', $str));
}
$max = max($digitsList);

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〃安静 2024-12-11 13:01:25

$nums=preg_split('/[^\d\.]+/',$string); //splits on non-numeric characters & allows for decimals
echo max($nums);

ETA：更新为允许以数字结尾或包含数字的“单词”（感谢戈登！）

$nums=preg_split('/[^\d\.]+/',$string); //splits on non-numeric characters & allows for decimals
echo max($nums);

ETA: updated to allow for "words" that end in or contain numbers (Thanks Gordon!)

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原来是傀儡 2024-12-11 13:01:25

<?php

$string = 'danger13 afno 1 900004';

preg_match_all('/[\d]+/', $string, $matches);

echo '<pre>'.print_r($matches,1).'</pre>';

$highest = array_shift($matches[0]);

foreach($matches[0] as $v) {
  if ($highest < $v) {
    $highest = $v;
  }
}

echo $highest;

?>

<?php

$string = 'danger13 afno 1 900004';

preg_match_all('/[\d]+/', $string, $matches);

echo '<pre>'.print_r($matches,1).'</pre>';

$highest = array_shift($matches[0]);

foreach($matches[0] as $v) {
  if ($highest < $v) {
    $highest = $v;
  }
}

echo $highest;

?>

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