计算字符串

Question

根据以下响应编辑问题：

我在文本文件中有一个字符串列表。我想计算这些字符串在另一个文本文件中的出现次数。

这是我在文件中的字符串示例

Red Car
No lake
Newjersey turnpike

这是我想要搜索上述字符串的文本文件：

I have a red car which I drove on newjersey 
turnpike. When I took exit 39 there was no 
lake. I drove my car on muddy roads which turned my red
car into brown. Driving on Newjersey turnpike can be confusing.

我正在寻找的答案是：

Newjersey turnpike 2
No lake 1
red car 2

如何在 python 中对其进行编程？非常感谢您的帮助！

这是我到目前为止所尝试的：

input_file_path = r'input_file.txt'
phrase_path = r'phrase_words.txt'
string_count_path =r'string_count.txt'

f = open(phrase_path,'r')
lines = f.readlines()
keys = []
for line in lines:
    key.append(line)
phrase_word = map(string.strip,map(str.lower,keys))
f.close()

dict={}
for key in phrase_words:
    dict[key]=0
f=open(input_file_path,'r')
lines = map(string.strip,map(str.lower,f.readlines()))
for w in lines:
    try:
        dict[w] += 1
    except KeyError:
        pass
f.close()

字符串已正确分配，但答案不正确..

phrase_words = ['red car', 'no lake', 'newjersey turnpike']

lines = ['i have a red car which i drove on newjersey', 'turnpike. when i took exit 39 there was no', 'lake. i drove my car on muddy roads which turned my red', 'car into brown. driving on newjersey turnpike can be confusing.']

dict = {'red car': 0, 'newjersery turnpike': 0, 'no lake': 0}

Answer 1

Python 2.7.1+ (r271:86832, Apr 11 2011, 18:13:53) 
[GCC 4.5.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> teststr = '''I have a red car which I drove on newjersey 
... turnpike. When I took exit 39 there was no 
... lake. I drove my car on muddy roads which turned my red
... car into brown. Driving on Newjersey turnpike can be confusing.
... '''
>>> teststr.count('Newjersey turnpike')
1
>>> 

Answer 2

>>> phrase_words
['red car', 'no lake', 'newjersey turnpike']
>>> lines
['i have a red car which i drove on newjersey', 'turnpike. when i took exit 39 there was no', 'lake. i drove my car on muddy roads which turned my red', 'car into brown. driving on newjersey turnpike can be confusing.']
>>> text = " ".join(lines) #join them in a str.
>>> {phrase: text.count(phrase) for phrase in phrase_words}
{'newjersey turnpike': 2, 'red car': 2, 'no lake': 1}

Answer 3

简单的方法，未经测试，但应该有效，假设没有交叉线词

f = open('keys.txt','r')
lines = f.readlines()
keys = []
for line in lines:
    keys.extend(line.split())
f.close()

dict = {}
for key in keys:
    dict[key]=0    

f = open('target.txt','r')
lines = f.readlines()
for line in lines:
    l = line.split()
    for w in l:
        try:
            dict[w] += 1
        except KeyError:
            pass
f.close()

Answer 4

如果您刚刚开始，请查看 Python 教程。对于具有任何编程经验水平、只想快速学习 Python 的人来说，这都是一本很好的读物。