如何从打开命令中查找文件路径
我需要获取 fo 变量中的文件路径，以便可以将路径传递给 unzip_file 函数。我如何获得这里的路径？
url = 'http://www.dtniq.com/product/mktsymbols_v2.zip'
open(url, 'r') do |fo|
puts "unzipfile "
unzip_file(fo, "c:\\temp11\\")
end
I need to get the path of the file in fo variable so that i can pass the path to the unzip_file function. how do i get the path here?
url = 'http://www.dtniq.com/product/mktsymbols_v2.zip'
open(url, 'r') do |fo|
puts "unzipfile "
unzip_file(fo, "c:\\temp11\\")
end
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至于如何做到这一点，我会这样做：
找出我正在处理的对象的类
<前><代码>ruby-1.9.2-p290 :001> tmp_file = open('tmp.txt', 'r')
=> #<文件：tmp.txt>
ruby-1.9.2-p290：001> tmp_file.class
=>文件
去查找该类的文档
Google 搜索：ruby 文件
返回
Class: File ruby-doc.org=>; www.ruby-doc.org/core/classes/File.html查看方法。有一个叫做
path->看起来很有趣如果我现在还没有找到答案，那么
大多数时候
1..3应该可以满足您的需求。一旦您学会阅读文档，您就可以更快地完成工作。它只是试图克服刚开始时进入文档的困难。In terms of how to do it I would do this:
Find out the class of the object I am dealing with
Go look up the documentation for that class
Google Search : ruby file
Which returns
Class: File ruby-doc.org=> www.ruby-doc.org/core/classes/File.htmlLook at the methods. There is one called
path-> looks interestingIf I haven't found an answer by now then
Most of the time
1..3should get you what you need. Once you learn to read the documentation you can do things a lot quicker. It's just trying to overcome how difficult it is to get into the docs when you first start.块中的
fo应该是Tempfile因此您可以使用路径方法：The
foin your block should be aTempfileso you can use thepathmethod: