使用 TBXML 解析子元素

发布于 2024-12-04 03:54:33 字数 1664 浏览 1 评论 0原文

我的 XML 如下所示：

<root>
<sets>
    <childSets>
        <childs>
            <child>
                <childId>11</childId>
        </child>
        <child>
            <childId>22</childId>
        </child>
        <child>
            <childId>33</childId>
        </child>
        <child>
            <childId>44</childId>
        </child>
[...]
    </childs>
</childSets>

    <childSets>
[...]
    </childSets>
</sets>
</root>

我想解析 child 的所有 childId 元素。

实际上，我的解析结果只是每个 childs 元素的第一个 childId：

[...]
do {
  if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
  [...]
        TBXMLElement *xmlChildId        = [TBXML childElementNamed:@"childId"           parentElement:child];
  [...]
  }
} while ((element = element->nextSibling));  
[...]

在本例中，我只得到 11。这里出了什么问题？

编辑1：

解决方案是找到子元素的第一个子元素并解析其下一个元素，如下所示：

这段代码位于 traverseElement 方法的 do while 循环中

do { [...]
        if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
        //find the first child
            if ((ChildPARENTELEMENT->firstChild)) {

            while (ChildOfCHILDELEMENT!=nil) {
                NSLog(@"....");

                 ChildOfCHILDELEMENT = [TBXML nextSiblingNamed:@"childs" searchFromElement:ChildOfCHILDELEMENT];

            }
        }
    }
while((element = element->nextSibling));

原文

My XML looks like this:

<root>
<sets>
    <childSets>
        <childs>
            <child>
                <childId>11</childId>
        </child>
        <child>
            <childId>22</childId>
        </child>
        <child>
            <childId>33</childId>
        </child>
        <child>
            <childId>44</childId>
        </child>
[...]
    </childs>
</childSets>

    <childSets>
[...]
    </childSets>
</sets>
</root>

I want to pars all childId elements of child.

Actually, the result of my parsing is just the first childId of every childs element:

[...]
do {
  if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
  [...]
        TBXMLElement *xmlChildId        = [TBXML childElementNamed:@"childId"           parentElement:child];
  [...]
  }
} while ((element = element->nextSibling));  
[...]

In this case, I just get 11. Whats wrong here?

EDIT 1:

The solution is to find the first child of the child element and to parse the next elements of this, here it is:

This code is in the do while loop of the method traverseElement

do { [...]
        if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
        //find the first child
            if ((ChildPARENTELEMENT->firstChild)) {

            while (ChildOfCHILDELEMENT!=nil) {
                NSLog(@"....");

                 ChildOfCHILDELEMENT = [TBXML nextSiblingNamed:@"childs" searchFromElement:ChildOfCHILDELEMENT];

            }
        }
    }
while((element = element->nextSibling));

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情域 2024-12-11 03:54:33

解决方案是找到子元素的第一个子元素并解析其下一个元素，如下所示：

这段代码位于 traverseElement 方法的 do while 循环中

do { [...]
    if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
    //find the first child
        if ((ChildPARENTELEMENT->firstChild)) {

        while (ChildOfCHILDELEMENT!=nil) {
            NSLog(@"....");

             ChildOfCHILDELEMENT = [TBXML nextSiblingNamed:@"childs" searchFromElement:ChildOfCHILDELEMENT];

        }
    }
}
while((element = element->nextSibling));

The solution is to find the first child of the child element and to parse the next elements of this, here it is:

This code is in the do while loop of the method traverseElement

do { [...]
    if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
    //find the first child
        if ((ChildPARENTELEMENT->firstChild)) {

        while (ChildOfCHILDELEMENT!=nil) {
            NSLog(@"....");

             ChildOfCHILDELEMENT = [TBXML nextSiblingNamed:@"childs" searchFromElement:ChildOfCHILDELEMENT];

        }
    }
}
while((element = element->nextSibling));

回复收藏 0 原文

从﹋此江山别 2024-12-11 03:54:33

您需要一个遍历所有子 xml 元素的内部循环。 childElementName:parentElement: 将仅返回具有该名称的第一个子元素。

尝试类似的方法：

[...]
do {
   if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
      [...]
      TBXMLElement *xmlChildId = [TBXML childElementNamed:@"childId" 
                                            parentElement:child];
      do {
         // Do nslog or whatever else on xmlChildId
         [...]

         // Find next child element to process
         xmlChildId = [TBXML nextSiblingName:@"childId" 
                           searchFromElement:xmlChildId];
      } while (xmlChildId != nil);
   }
} while ((element = element->nextSibling));  
[...]

You need an inner loop that goes through all the child xml elements. The childElementName:parentElement: will only return the first child with that name.

Try something like:

[...]
do {
   if ([[TBXML elementName:element] isEqualToString:@"childSet"]) {
      [...]
      TBXMLElement *xmlChildId = [TBXML childElementNamed:@"childId" 
                                            parentElement:child];
      do {
         // Do nslog or whatever else on xmlChildId
         [...]

         // Find next child element to process
         xmlChildId = [TBXML nextSiblingName:@"childId" 
                           searchFromElement:xmlChildId];
      } while (xmlChildId != nil);
   }
} while ((element = element->nextSibling));  
[...]

回复收藏 0 原文

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