PHP CURL 发布返回结果，但我需要空结果
我正在做curl post，但问题是我需要返回空结果，以便我可以为我的ajax请求结果回显另一个值：
下面是代码：
$ch = curl_init("http://www.rankreport.com.au/ajax/add_new_lead");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "lead_company_id=1&lead_business=1234&lead_first_name=asdf&lead_website=12314.com&lead_phone=1234&[email protected]&lead_package=seo");
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_exec($ch);
curl_close($ch);
echo 'error 3';
当我这样做时，我得到以下结果：
{"lead_date":1315637343,"lead_company_id":"1","lead_business":"1234","lead_first_name":"asdf","lead_last_name":"","lead_website":"12314.com","lead_phone":"1234","lead_email":"[email protected]","lead_package":"seo"} 3
如何设置卷曲选项，以便它不返回任何卷曲结果？
I'm doing curl post but the problem is that I need to return empty results so I can echo out another value for my ajax request results:
below is the code:
$ch = curl_init("http://www.rankreport.com.au/ajax/add_new_lead");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "lead_company_id=1&lead_business=1234&lead_first_name=asdf&lead_website=12314.com&lead_phone=1234&[email protected]&lead_package=seo");
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_exec($ch);
curl_close($ch);
echo 'error 3';
When I do this, I'm getting below results:
{"lead_date":1315637343,"lead_company_id":"1","lead_business":"1234","lead_first_name":"asdf","lead_last_name":"","lead_website":"12314.com","lead_phone":"1234","lead_email":"[email protected]","lead_package":"seo"} 3
How do set curl options so that it doesn't return any curl results?
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设置
CURLOPT_RETURNTRANSFER：Set
CURLOPT_RETURNTRANSFER:使用
CURLOPT_RETURNTRANSFER = true将返回的内容作为返回值($ch)而不是输出。Use
CURLOPT_RETURNTRANSFER = trueto have the returned content as a return value ($ch) instead of output.