maven 程序集依赖项设置为空

Question

我正在尝试设置一个我认为简单的程序集，从多个模块中获取 jar 并将它们放入 zip 内的特定文件夹中。生成的程序集应如下所示：
ir4job\
ir4job\app_lib\
ir4job\app_lib\ jar 文件放在这里

但是当生成程序集时，maven 给了我一个空的 zip 文件 程序

集描述符：

<assembly>
  <!-- ir4job folder contents -->
  <id>ir4job-app</id>
  <formats>
    <format>zip</format>
  </formats>
  <includeBaseDirectory>false</includeBaseDirectory>

  <moduleSets>
    <moduleSet>
      <binaries>
        <dependencySets>
          <dependencySet>
            <outputDirectory>ir4job/app_lib</outputDirectory>
          </dependencySet>
        </dependencySets>
      </binaries>
    </moduleSet>
  </moduleSets>
</assembly>

pom 文件：

<project>
  <modelVersion>4.0.0</modelVersion>

  <groupId>glb</groupId>
  <artifactId>Release</artifactId>
  <packaging>pom</packaging>
  <name>release</name>
  <version>1.0</version>

  <parent>
.... parent info ....
  </parent>

  <dependencies>
... various dependencies ...
  </dependencies>

  <build>
    <plugins>
      <plugin>
        <groupId>org.apache.maven.plugins</groupId>
        <artifactId>maven-assembly-plugin</artifactId>

        <configuration>
          <appendAssemblyId>false</appendAssemblyId>
          <descriptors>
            <descriptor>ir4job-app.xml</descriptor>
          </descriptors>
        </configuration>
        <executions>
          <execution>
            <id>do-release</id>
            <phase>package</phase>
            <goals>
              <goal>single</goal>
            </goals>
          </execution>
        </executions>
      </plugin>

    </plugins>
  </build>
</project>

我很确定我在这里错过了一些简单的东西...它是什么？

Answer 1

乍一看，您似乎缺少要包含的文件集。例如：

<assembly>
    <id>ir4job-app</id>
    <formats>
        <format>zip</format>
    </formats>
    <includeBaseDirectory>false</includeBaseDirectory>

    <fileSets>
        <fileSet>
            <directory>path/to/folder/relative/to/project/root/ir4job/app_lib</directory>
            <outputDirectory>ir4job/app_lib</outputDirectory>
            <includes>
                <include>*.jar</include>
            </includes>
        </fileSet>
    </fileSets>
</assembly>

您需要为要包含的每个目录提供一个文件集（除非它们位于同一父目录下）。其语法类似于：

...
<includeBaseDirectory>true</includeBaseDirectory>
....
<fileSet>
    <directory>path/to/folder/relative/to/project/root/ir4job</directory>
    <includes>
        <include>**/*.jar</include>
    </includes>
</fileSet>
...

---

edit #1:

使用 maven-dependency-plugin 将依赖项复制到文件夹的工作示例：

         <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-dependency-plugin</artifactId>
            <executions>
                <execution>
                    <id>copy-dependencies-for-assembly</id>
                    <phase>generate-resources</phase>
                    <goals>
                        <goal>copy-dependencies</goal>
                    </goals>
                    <configuration>
                        <outputDirectory>target/libs</outputDirectory>
                        <stripVersion>true</stripVersion>
                    </configuration>
                </execution>
            </executions>
        </plugin>

---

注意：您还可以使用配置选项来限制复制的依赖项，例如

...
<configuration>
    ...
    <includeGroupIds>com.mycompany,org.springframework,org.hibernate</includeGroupIds>
</configuration>
...

You can also limit by artifactId、分类器等

---

编辑#2：

解决方案

更好的答案可能只是将您的 dependencySet 标记拉高几个级别，如下所示：

<assembly>
    <!-- ir4job folder contents -->
    <id>ir4job-app</id>
    <formats>
        <format>zip</format>
    </formats>
    <includeBaseDirectory>false</includeBaseDirectory>

    <dependencySets>
        <dependencySet>
            <outputDirectory>ir4job/app_lib</outputDirectory>
        </dependencySet>
    </dependencySets>
 </assembly>