Web数据库子查询

Question

我正在努力使用 JavaScript 函数从 2 个不同的查询中获取数据。如果我在函数中单独执行查询，我只能从第二个查询中的第一个查询中获得最后的结果。我得出的结论是，我必须对这两个查询进行子查询，以便该函数能够正常运行。

以下是两个查询 (popt.products_options_id = prodOpId)：

tx.executeSql('
SELECT DISTINCT
popt.products_options_id, 
popt.products_options_name 
FROM
products_options popt, 
products_attributes patrib 
WHERE
patrib.products_id="1" 
AND
patrib.options_id = popt.products_options_id 
AND
popt.language_id = "1"  
ORDER BY 
popt.products_options_name',
[], function (tx, results) {


tx.executeSql('
SELECT
pov.products_options_values_id,
pov.products_options_values_name, 
patrib.options_values_price, 
patrib.price_prefix 
FROM
products_attributes patrib, 
products_options_values pov 
WHERE
patrib.products_id = "1" 
AND
patrib.options_id ='+ prodOpId + ' 
AND
patrib.options_values_id = pov.products_options_values_id 
AND
pov.language_id = "1"', 
[], function (tx, results) {

Answer 1

我解决了当前查询的问题：

tx.executeSql('
SELECT 
popt.products_options_id, 
popt.products_options_name,
pov.products_options_values_id, 
pov.products_options_values_name, 
patrib.options_values_price,
patrib.price_prefix 

FROM
products_options popt, 
products_attributes patrib, 
products_options_values pov 

WHERE 
patrib.products_id="1"

AND 
patrib.options_id = popt.products_options_id 

AND 
patrib.options_values_id = pov.products_options_values_id

AND 
popt.language_id = "1"

ORDER BY 
popt.products_options_name',

[], function (tx, results) {